Answer:
peux tu me donner plus de précisions stp concernant le détail de calcul que tu souhaite avoir ?
Explanation:
Respuesta:
60°
Explicación:
Paso 1: Información dada
- Distancia recorrida (d): 2000 cm
- Fuerza aplicada (F): 80 N
- Trabajo realizado (W): 800 J
Paso 2: Convertir "d" a metros
Usaremos el factor de conversión 1 m = 100 cm.
2000 cm × 1 m/100 cm = 20 m
Paso 3: Calcular el ángulo entre la cuerda y el suelo (θ)
W = F × d × cosθ
800 J = 80 N × 20 m × cosθ
θ = 60°
Answer:
Keq = 0.053
7.3 kJ/mol
Explanation:
Let's consider the following isomerization reaction.
glucose 6‑phosphate ⇄ glucose 1 - phosphate
The concentrations at equilibrium are:
[G6P] = 0.19 M
[G1P] = 0.01 M
The concentration equilibrium constant (Keq) is:
Keq = [G1P] / [G6P]
Keq = 0.01 / 0.19
Keq = 0.053
We can find the standard free energy change, ΔG°, of the reaction mixture using the following expression.
ΔG° = -R × T × lnKeq
ΔG° = -8.314 J/mol.K × 298 K × ln0.053
ΔG° = 7.3 × 10³ J/mol = 7.3 kJ/mol
1 mole ----------- 22.4 L ( at STP )
3.75 moles ----- ?
3.75 x 22.4 / 1 => 84.0 L