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timurjin [86]
3 years ago
5

When NH3(g) reacts with N2O(g) to form N2(g) and H2O(g), 105 kcal of energy are evolved for each mole of NH3(g) that reacts. Wri

te a balanced equation for the reaction with an energy term in kcal as part of the equation.
Chemistry
1 answer:
Ganezh [65]3 years ago
7 0

Answer : The balanced chemical equation is,

2NH_3(g)+3N_2O(g)\rightarrow 4N_2(g)+3H_2O(g)+210kcal

Explanation :

Balanced chemical equation : It is defined as the number of atoms of individual elements present on the reactant side must be equal to the number of atoms of individual elements present on product side.

The given unbalanced chemical reaction is,

NH_3(g)+N_2O(g)\rightarrow N_2(g)+H_2O(g)+105kcal

This chemical reaction is an unbalanced reaction because in this reaction, the number of atoms of individual elements are not balanced.

In order to balanced the chemical reaction, the coefficient 2 is put before the NH_3, the coefficient 3 is put before the N_2O\text{ and }H_2O and the coefficient 4 is put before the N_2.

The energy evolved in this reaction = 105Kcal\times 2=210Kcal

Thus, the balanced chemical reaction will be,

2NH_3(g)+3N_2O(g)\rightarrow 4N_2(g)+3H_2O(g)+210kcal

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B. Fluorine (F) element easily gains one electron to for a negative ion.

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In photosynthesis, the reactants are more stable than the products. However, both the products and reactants are stable. Therefo
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Answer:

A.) Absorb and store

Explanation:

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<em />

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3 0
4 years ago
Read 2 more answers
A compound decomposes by a first-order process. What is the half-life of the compound if 25.0% of the compound decomposes in 60.
amid [387]

Answer : The half-life of the compound is, 145 years.

Explanation :

First we have to calculate the rate constant.

Expression for rate law for first order kinetics is given by:

k=\frac{2.303}{t}\log\frac{a}{a-x}

where,

k = rate constant  = ?

t = time passed by the sample  = 60.0 min

a = let initial amount of the reactant  = 100 g

a - x = amount left after decay process = 100 - 25 = 75 g

Now put all the given values in above equation, we get

k=\frac{2.303}{60.0}\log\frac{100g}{75g}

k=4.79\times 10^{-3}\text{ years}^{-1}

Now we have to calculate the half-life of the compound.

k=\frac{0.693}{t_{1/2}}

4.79\times 10^{-3}\text{ years}^{-1}=\frac{0.693}{t_{1/2}}

t_{1/2}=144.676\text{ years}\approx 145\text{ years}

Therefore, the half-life of the compound is, 145 years.

8 0
4 years ago
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