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Answer:
igneous rock CAN become sedimentary rock through a process called ROCK CYCLE.
Explanation:
Rocks can be defined as solid structures of minerals that are formed naturally over a period of time. They are grouped into three main types which includes the following:
- igneous rock
- sedimentary rocks and
- metamorphic rocks.
Rocks are capable of transforming from one type to another through a process known as rock cycle. There are two forces that brings about this process which includes:
- The internal force : this is the Earth’s internal heat engine, which moves material around in the core and the mantle and leads to slow but significant changes within the crust.
- The external force: this is the the hydrological cycle, which is the movement of water, ice, and air at the surface, and is powered by the sun.
Molten magma cools to form either extrusive igneous rock or intrusive igneous rock. With time they undergo weathering, eroded, transported, and then deposited as sediments which are being compressed and cemented into SEDIMENTARY ROCKS. Again through the above mentioned forces, different kinds of rocks are either uplifted, to be re-eroded, or buried deeper within the crust where they are heated up, squeezed, and changed into METAMORPHIC ROCK.
Therefore the material in this sedimentary rock found in Rhombus planet used to be in igneous rock deep in Rhombus's interior due to continuous rock cycling on the planet. I hope this helps, thanks.
Taking into account the definition of dilution, the concentration of the new solution is 1 mol/L.
<h3>Dilution</h3>
When it is desired to prepare a less concentrated solution from a more concentrated one, it is called dilution.
Dilution is the process of reducing the concentration of solute in solution, which is accomplished by simply adding more solvent to the solution at the same amount of solute.
In a dilution the amount of solute does not change, but as more solvent is added, the concentration of the solute decreases, as the volume (and weight) of the solution increases.
A dilution is mathematically expressed as:
Ci×Vi = Cf×Vf
where
- Ci: initial concentration
- Vi: initial volume
- Cf: final concentration
- Vf: final volume
<h3>Final volume</h3>
In this case, you know:
- Ci= 6 mol/L
- Vi= 200 mL
- Cf= ?
- Vf= 1 L (1000 mL) water + 200 mL of HCL= 1200 mL
Replacing in the definition of dilution:
6 mol/L× 200 mL= Cf× 1200 mL
Solving:
(6 mol/L× 200 mL)÷ 1200 mL= Cf
<u><em>1 mol/L= Cf</em></u>
In summary, the concentration of the new solution is 1 mol/L.
Learn more about dilution:
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Answer:
Explanation:
Hello!
In this case, since the equation for the ideal gas is:
For each gas, given the total volume, temperature (28.1+273.15=301.25K) and moles, we can easily compute the partial pressure as shown below:
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Answer: E = 2.455 x 10^5 N/C
Explanation:
q1 = 1.2x10^-7C
q2 = 6.2x10^-8C
Electric field, E = kQ/r²
where k = 9.0x10^9
since the location is (27 - 5)cm from q1
hence electric field, E1 = k*q1/r²
E1= (9x10^9 x 1.2x10^-7)/(0.22)² = 22314.05 N/C
for q2:
E1 = k*q2/r²
E2 at 5cm
E2 = (9x10^9 x 6.2x10^-8)/(0.05)² = 223200 N/C
Hence, the total electric field at 5cm position is
E = E1 + E2
E = 22314.05 + 223200 = 245514.05 N/C
E = 2.455 x 10^5 N/C
