Angles ∠MOK and ∠NOL are identical by opposite angle theorem.
∠M = ∠N through given information
∠MKO and ∠NLO are congruent. Since the other two angles of each triangle are equivalent, the last angle must be equivalent to the last angle of the other triangle. (180 - ∠1 -∠2 = ∠3); you could also prove ∠MKO = ∠NLO by stating that the opposite sides of the two angles are congruent.
ΔMKO and ΔNLO by Angle-Angle-Side theorem
since ΔMKO and ΔNLO, all corresponding parts of both triangles are congruent, so therefore MO ≅ NO
Simplifying
7x + -4y = 23
Solving
7x + -4y = 23
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '4y' to each side of the equation.
7x + -4y + 4y = 23 + 4y
Combine like terms: -4y + 4y = 0
7x + 0 = 23 + 4y
7x = 23 + 4y
Divide each side by '7'.
x = 3.285714286 + 0.5714285714y
Simplifying
x = 3.285714286 + 0.5714285714y
Step-by-step explanation:
area of missed triangle =1/2×2×4=4 cm2
area of whole rectangle =4×8=32 cm2
area of shape =32_4 =28cm2
60 <span>$8 an hour plus $12 an hour for every hour of overtime. Overtime hours are any hours more than 40 </span>
Cos(35) = x/6
or 6 * cos(35) = x
