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3 years ago

A card is selected at random from a deck of 52 playing cards, the probability that a face card selected is ______________

Mathematics

1 answer:

ratelena [41]3 years ago

7 0

Answer:

Step-by-step explanation:

There are 12 face cards in a deck out of 52, so 12/52 would be the probability

hope this helps :)

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Consider the line y = x – 4. A line parallel to the graph of the line would have a slope of . A line perpendicular to the graph

kotykmax [81]

Answer:

A. 1

B. $-1$ .

Step-by-step explanation:

We have been given an equation of a line $y=x-4$ .

A. We know that slope of parallel lines is always equal,

We can see that slope of our given line is 1, therefore the slope of the line parallel to our given line would be 1.

B. We know that the product of slopes of two perpendicular lines is $-1$ .

Let m represent slope of perpendicular to our given line, then:

$m\times 1=-1$

$m=-1$

Therefore the slope of the line perpendicular to our given line would be $-1$ .

4 2

2 years ago

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The radius of a circle is the distance from its center to the edge of the circle. The diameter is the length of a line segment t

katovenus [111]

The relation is that the diameter is twice the length of the radius.

To make more proof, look at the attached image below.

5 0

3 years ago

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We wish to give a 90% confidence interval for the mean value of a normally distributed random variable. We obtain a simple rando

coldgirl [10]

Answer: $(9.27025,\ 11.12975)$

Step-by-step explanation:

Given : Sample size : n= 9

Degree of freedom = df =n-1 =8

Sample mean : $\overline{x}=10.2$

sample standard deviation : $s= 1.5$

Significance level ; $\alpha= 1-0.90=0.10$

Since population standard deviation is not given , so we use t- test.

Using t-distribution table , we have

Critical value = $t_{\alpha/2, df}=t_{0.05 , 8}=1.8595$

Confidence interval for the population mean :

$\overline{x}\pm t_{\alpha/2, df}\dfrac{s}{\sqrt{n}}$

90% confidence interval for the mean value will be :

$10.2\pm (1.8595)\dfrac{1.5}{\sqrt{9}}$

$10.2\pm (1.8595)\dfrac{1.5}{3}$

$10.2\pm (1.8595)(0.5)$

$10.2\pm (0.92975)$

$(10.2-0.92975,\ 10.2+0.92975)$

$(9.27025,\ 11.12975)$

Hence, the 90% confidence interval for the mean value= $(9.27025,\ 11.12975)$

6 0

3 years ago

Jun used 56 cm of ribbon to go around the edge of a rectangular lid. The lid was 13 cm long. What is the width of the lid?

maksim [4K]

Answer:

The width of the rectangular lid is 15 cm.

Step-by-step explanation:1. Let's review the information given to us to answer the question correctly:

Length of the ribbon used by Jun = 56 cmLength of the rectangular lid = 13 cm

2. What is the width of the lid? The ribbon used by Jun is equivalent to the perimeter of the rectangular lid, therefore:Perimeter = 2 * Length + 2 * WidthReplacing with the values we have:56 = 2 * 13 + 2 * Width56 = 26 + 2Width2Width = 56 - 262Width = 30Width = 30/2Width = 15

5 0

2 years ago

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4k + 15 greater than -2k + 3

ioda

Answer:

k>-2

Step-by-step explanation:

4k+15>-2k+3

4k-(-2k)+15>3

4k+2k+15>3

6k+15>3

6k>3-15

6k>-12

k>-12/6

k>-2

8 0

3 years ago