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miss Akunina [59]
3 years ago
6

Who suggested the idea of continental drift and the existence of an original supercontinent? NEED HELP ASAP WILL MARK BRAINLIEST

Chemistry
1 answer:
Grace [21]3 years ago
4 0

Answer:

B)Wegener

Explanation:

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Pls help and i will mark brainliest
myrzilka [38]

Answer:

No. 3 lithium

Explain that lithium has 3 protons and 3 electrons. There are 2 electrons on the first energy level and 1 electron on the second

No. 4 Hydrogen (H) and helium (He) have a valence shell containing one and two electrons respectively. They make up the first period (row) of the periodic table. Their valence electron/s are in the first energy level (n=1) , as is denoted by 1s1 and 1s2 .

<em>That</em><em>'</em><em>s</em><em> </em><em>all</em><em> </em><em>i</em><em> </em><em>dont</em><em> </em><em>know</em><em> </em><em>if</em><em> </em><em>this</em><em> </em><em>is</em><em> </em><em>right</em><em> </em><em>though</em><em>.</em><em> </em>

6 0
3 years ago
Read 2 more answers
The density of gold is 19.3g/cm3. What is the mass of 11.3 cm3 of gold?
Alex_Xolod [135]

Answer:

218.09g

Explanation:

the formula for density is mass/volume

you have volume so rlly what you have is 19.3g/cm3=m/11.3cm3

so mass equals density x volume

and 19.3 x 11.3 = 218.09

3 0
3 years ago
What kind of liquid promote corrosion
MaRussiya [10]
Is this the whole answer?
7 0
4 years ago
A biochemist carefully measures the molarity of magnesium ion in 47, mL of cell growth medium to be 97. ??. Unfortunately, a car
serg [7]

Complete Question

The complete question is shown on the first uploaded image

Answer:

 Answer: 760 uM

Explanation:

the addition of solvent to a solution in a such away that the volume of the solution increases and the concentration decreases is a process know as dilution

The concentration and the volume of the dilute and concentrated solution are given below as follows

     C_{1}V_{1}                               = C_{f}V_{f}

Concentrated solution          Dilute solution

Given that  M1 = 97.0uM

                  V1 = 47.0 mL

                 V2 = 6.0 mL

                 M2  = ?

Therefore M1V1   = M2V2

                M2      = M1V1/V2

                 M2 = (97*47)/6

               M2 = 760 uM

Answer: 760 uM

               

5 0
4 years ago
Find the enthalpy of neutralization of HCl and NaOH. 87 cm3 of 1.6 mol dm-3 hydrochloric acid was neutralized by 87 cm3 of 1.6 m
olga nikolaevna [1]

Explanation:

The reaction equation for the given reaction will be as follows.

               HCl + NaOH \rightarrow NaCl + H_{2}O

Each mole of both HCl and NaOH gives one mole of water.

Also, it is given that 1 liter of NaOH and HCl solution contains 1.6 mol dm^{-3} of NaOH (HCl).

It is known that 1 cm^{3} = 0.001 liter. So, 87 cm^{3} = 0.087 liter.

Hence, number of moles of water obtained from the given reaction are as follows.

                  0.087 liter × 1.6 mol = 0.1392 moles

            No. of moles = \frac{mass}{molar mass of water}

                0.1392 moles = \frac{mass}{18 g/mol}

                       mass = 2.5056 g

Now, volume of water present before the reaction is 2 \times 0.087 liter = 0.174 liter or 0.174 Kg (as density is 1 Kg/cm^{3}) or 174 g (as 1 kg = 1000 g).

Therefore, total weight of water present = 2.5056 g + 174 g = 176.5056 g

Formula to calculate enthalpy of neutralization is as follows.

                Enthalpy of neutralization = mS \Delta T

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where,            m = mass

                       S = specific heat capacity

                   \Delta T = change in temperature

Putting the given values in the formula as follows.

       Enthalpy of neutralization = mS \Delta T

                     = 176.5056 g \times 4.18 J/K g \times (317.4 K - 298 K)              

                                                           = 14333.73 J

   or,                                                    = 14.33 kJ

Thus, we can conclude that the enthalpy of neutralization of given reaction is 14.33 kJ.

5 0
4 years ago
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