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DanielleElmas [232]
4 years ago
12

From your observations of the simulation, which strategy was most effective for quickly and efficiently producing ammonia? Why d

o you think this strategy is most effective?
Chemistry
1 answer:
Bogdan [553]4 years ago
8 0

Answer:

The electrochemical synthesis of ammonia from nitrogen under mild conditions using renewable electricity is an attractive alternative to the energy-intensive Haber–Bosch process, which dominates industrial ammonia production.

Explanation:

However, there are considerable scientific and technical challenges facing the electrochemical alternative, and most experimental studies reported so far have achieved only low selectivities and conversions. The amount of ammonia produced is usually so small that it cannot be firmly attributed to electrochemical nitrogen fixation rather than contamination from ammonia that is either present in air, human breath or ion-conducting membranes, or generated from labile nitrogen-containing compounds (for example, nitrates, amines, nitrites and nitrogen oxides) that are typically present in the nitrogen gas stream, in the atmosphere or even in the catalyst itself. Although these sources of experimental artefacts are beginning to be recognized and managed, concerted efforts to develop effective electrochemical nitrogen reduction processes would benefit from benchmarking protocols for the reaction and from a standardized set of control experiments designed to identify and then eliminate or quantify the sources of contamination.

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A weather balloon is filled with helium that occupies a volume of 5.00 × 10^4 L at 0.995 atm and 32.0°C. After it is released, i
DaniilM [7]

Answer:

The new volume is 5.913*10^4 L

Explanation:

Step 1: Write out the formula to be used:

Using general gas equation;

P1V1 / T1 =P2V2 /T2

V2 = P1V1T2 / P2T1

Step 2: write out the values given and convert to standard unit's where necessary

P1 = 0.995atm

P2 0.720atm

V1 = 5*10^4 L

T1 = 32°C = 32+ 273 = 305K

T2 = -12°C = -12 + 273 = 261K

Step 3: Equate your values and do the calculation:

V2 = 0.995 * 5*10^4 * 261 / 0.720 * 305

V2 = 1298.475 * 10^4 / 219.6

V2 = 5.913 * 10^4 L

So the new volume of the balloon is 5.913*10^4 L

3 0
3 years ago
Element X has the following valence electron configuration: [core]ns2np5. Element M has the following valence electron configura
alex41 [277]

Answer:

The kind of ionic compound formed is MX2.

Explanation:

Element X electron  configuration is represented as [core] ns2np5. The group in the periodic table this element belong to is group 7A.  The element group is called the halogen family. Element X cannot be stated specifically, because the number is represented with n.  Element X will behave as an anions when it react with a metal(cations). Element X has a charge of -1. The element X will gain electron when it bond with a metal. Element X is a non metal . Elements  in this group are fluorine, chlorine, bromine, iodine , astatine, and tennessine . The element X have 7 valency electrons.

Element M electronic configuration is represented as  [core]ns2. The group in the periodic table this element belong to is group 2A . The element  group is called the alkaline earth metals family . Element M will behave as a cation when it bond with a non metal. Element M is a metal , therefore it will likely lose electron to form cations during bonding . The charge of element M is 2+. Element M is positively charged. Elements that belong to this group includes beryllium, magnesium, calcium, strontium, barium and radium.  Element M has 2 valency electrons.

The reaction between this 2 ions will likely form an ionic compound . The element M is the cations while the element X is the anions. The element M will lose 2 electron while 2 atoms of element  X will gain 2 electrons.Element M will lose 2 electron to attain a stable configuration while 2 atoms of element X will gain a single electron each to attain a stable configuration.

M²+ and F- . This will form MX2 when you cross multiply the charge. The kind of ionic compound formed is MX2.

6 0
3 years ago
Hello! I need a bit of help and Im kinda in a bit of a hurry so please help! Thank you :D
Scorpion4ik [409]
The first one is substance 3
The second one is Oxygen, Helium, and carbon dioxide
The third one is the oil floats on top of the water
8 0
3 years ago
Read 2 more answers
Consider a solution that is 0.05 M HCl. Your goal is to neutralize 1 L of this solution (i.e. bring the pH to 7). You also have
Ilia_Sergeevich [38]

Answer:

The volume of NaOH required is - 0.01 L

Explanation:

At equivalence point ,

Moles of HCl = Moles of NaOH

Considering :-

Molarity_{HCl}\times Volume_{HCl}=Molarity_{NaOH}\times Volume_{NaOH}

Given  that:

Molarity_{NaOH}=5\ M

Volume_{NaOH}=?\ L

Volume_{HCl}=1\ L

Molarity_{HCl}=0.05\ M

So,  

Molarity_{HCl}\times Volume_{HCl}=Molarity_{NaOH}\times Volume_{NaOH}

0.05\times 1=5\times Volume_{NaOH}

Volume_{NaOH}=\frac{0.05\times 1}{5}=0.01\ L

<u>The volume of NaOH required is - 0.01 L</u>

3 0
3 years ago
A bowling ball rests on the floor. The bowling ball is given a push.
lyudmila [28]

Answer:

A. It will move.

8 0
3 years ago
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