coolio
so each term is ound by subtracting 13 from the previous term
an aritmetic sequence can be written as
were
is the nth term
is the first term
d is common difference, which can also be found by doing 
n=wich term
we know that and we can find d
, 
so te general term is 
which can also be expanded and written as 
Answer:
1/4 barrels of almonds
Step-by-step explanation:
(3/4)/3=(3/4)(1/3)=3/12=1/4
Answer:
the answer is (-2,6) this is way he range
Answer:
The nth term is Tn = 2[T(n- 1) -2]
The next term is 356
Step-by-step explanation:
Given
Terms: 15,26,48,92,180
Solving (a) : The recursive n term
We have:
T1 = 15
T2 = 26 = 13 * 2 = (15 - 2) * 2
T3 = 48 = 24 * 2 = (26 - 2) * 2
T4 = 92 = 46 * 2 = (48 - 2) * 2
T5 = 180 = 90 * 2 = (92 - 2) * 2
So, the nth term can be represented as:
Tn = [T(n-1) - 2] * 2
Tn = 2[T(n-1) - 2]
The next term is the 6th term.
So, substitute 6 for n in the above formula.
T6 = 2 * [T(6 - 1) - 2]
T6 = 2 * [T5 - 2]
Substitute 180 for T5
T6 = 2 * (180 - 2)
T6 = 2 * 178
T6 = 356
