Answer:
C4H3O
Explanation:
Data obtained from the question include:
Carbon (C) = 68.85%
Hydrogen (H) = 4.95%
Since the vaccine contains carbon, hydrogen and oxygen, the remaining percentage will be for oxygen. The percentage of oxygen will be:
Oxygen (O) = 100 - (68.85 + 4.95)
= 26.2%
The empirical formula for the vaccine can be obtained as follow:
Carbon (C) = 68.85%
Hydrogen (H) = 4.95%
Oxygen (O) = 26.2%
Divide the above by their individual molar mass as shown below:
C = 68.85/12 = 5.7375
H = 4.95/1 = 4.95
O = 26.2/16 = 1.6375
Next, divide by the smallest number as shown below:
C = 5.7375/1.6375 = 4
H = 4.95/1.6375 = 3
O = 1.6375/1.6375 = 1
Therefore, the empirical formula for the vaccine is C4H3O
Answer:
No.
Explanation:
According to the formula б/X=б/√n, as more measurements are made, the uncertainty gets smaller.
Not so. Dissolved gases trapped in the minerals provide the pressure for an explosive eruption.
The recessive allele is the short pea plant gene.
The dominant allele is the tall pea plant gene