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Kaylis [27]
3 years ago
9

What change occurs to an atom when it forms negative ion​

Chemistry
2 answers:
Artist 52 [7]3 years ago
6 0

Answer:

The outer shells of non-metal atoms gain electrons when they form ions. The ions formed are negative because they have more electrons than protons

Explanation:

IrinaVladis [17]3 years ago
6 0
Ions are formed when atoms gain or lose electrons. Gaining electrons changes an atom into a negative ion. Losing electrons changes an atom into a positive ion. Individual atoms often do not form ions by themselves.
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Nitrogen (N2) and hydrogen (H2) react to form ammonia (NH3). Consider a mixture of six nitrogen molecules and six hydrogen molec
Nezavi [6.7K]

Answer:

a)  No molecules of hydrogen

b) four molecules of ammonia

c) four left molecules of nitrogen.

Explanation:

The balanced reaction between nitrogen and hydrogen molecules to give ammonia molecules is:

N_{2}(g)+3H_{2}(g) -->2NH_{3}

Thus one molecule of nitrogen will react with three molecules of hydrogen to give two molecules of ammonia.

We have six molecules of each nitrogen and hydrogen in the closed container and they undergo complete reaction it means the limiting reagent is hydrogen. For six molecules of nitrogen, eighteen molecules of hydrogen will be required.

So six molecules of hydrogen will react with two molecules of nitrogen to give four molecules of ammonia.

The product mixture will have

a) No molecules of hydrogen

b) four molecules of ammonia

c) four left molecules of nitrogen.

7 0
3 years ago
What would be the temperature of 0.6 moles of fluorine that occupy 15 L at 2,300 mmHg?
Anna [14]

Answer: The temperature of 0.6 moles of fluorine that occupy 15 L at 2,300 mmHg is 920 K

Explanation:

According to ideal gas equation:

PV=nRT

P = pressure of gas = 2300 mm Hg = 3.02 atm  (760mmHg=1atm)

V = Volume of gas = 15 L

n = number of moles = 0.6

R = gas constant =0.0821Latm/Kmol

T =temperature = ?

T=\frac{PV}{nR}

T=\frac{3.02atm\times 15L}{0.0821Latm/K mol\times 0.6mol}=920K

Thus the temperature of 0.6 moles of fluorine that occupy 15 L at 2,300 mmHg is 920 K

8 0
3 years ago
Which one of the following statements is FALSE? a In a neutralization reaction, an acid reacts with base to produce a salt and H
pishuonlain [190]

Answer: Option (c) is the correct answer.

Explanation:

HF is a weak acid and not a strong acid. This is because fluorine is a highly electronegative atom and when it combines with a hydrogen atom then it will attract the valence electron of hydrogen atom more towards itself.

As a result, it will not dissociates easily to give hydrogen ion. Hence, it acts as a weak acid.

A neutralization reaction is defined as a reaction in which an acid reacts with a base to give salt and water. For example, HCl + NaOH \rightarrow NaCl + H_{2}O

It is true that, spectator ions "appear in the total ionic equation for a reaction, but not in the net ionic equation".

Titration is defined as a process in which concentration of an unknown solution is determined using a solution of known concentration.

Thus, we can conclude that the statement HF, HCl, and HNO3 are all examples of strong acids, is false.

7 0
3 years ago
A particular power source creates electricity through the use of giant magnets that are rotated to create a flow of electrons. T
Sloan [31]
From the electric generator to electric outlets in homes
6 0
2 years ago
Read 2 more answers
A 215-g sample of copper metal at some temperature is added to 26.6 g of water. The initial water temperature is 22.22 oC, and t
andrezito [222]

The initial temperature of the copper metal was 27.38 degrees.

Explanation:

Data given:

mass of the copper metal sample = 215 gram

mass of water = 26.6 grams

Initial temperature of water = 22.22 Degrees

Final temperature of water = 24.44 degrees

Specific heat capacity of water = 0.385 J/g°C

initial temperature of copper material , Ti=?

specific heat capacity of water = 4.186 joule/gram °C

from the principle of:

heat lost = heat gained

heat gained by water is given by:

q water = mcΔT

Putting the values in the equation:

qwater = 26.6 x 4.186 x (2.22)

qwater = 247.19 J

qcopper = 215 x 0.385 x (Ti-24.4)

              = 82.77Ti - 2019.71

Now heat lost by metal = heat gained by water

82.77Ti - 2019.71 = 247.19

Ti = 27.38 degrees

8 0
3 years ago
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