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3 years ago

Please answer as quick as possible

Chemistry

2 answers:

OverLord2011 [107]3 years ago

4 0

Answer:

A - potassium........ M

pantera1 [17]3 years ago

4 0

Answer:

POTASSIUM

Explanation:

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densk [106]

YOu should use the Graham's Law of Diffusion

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I'm not sure if your professor gives density or molar mass for this problem? You need M2 and M1 to solve for the rates of diffusion.

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4 years ago

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3 years ago

PLEASE ANSWER 80 POINTS

skelet666 [1.2K]

It is Z1 and Z4 only... Answer is number 1

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3 years ago

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5. Calcule las concentraciones cuando se alcanza el equilibrio si partimos de unas concentraciones iniciales [A]=[B]=1M ; [C]=[D

g100num [7]

Las concentraciones en el equilibrio para la reacción química presentada son:

$[A] = [B] = 1-x = 1-0.69 = 0.31 M\\[C] = [D] = x = 0.69 M$

Consideremos la siguiente reacción química genérica:

A + B ⇄ C + D

Para calcular las concentraciones en el equilibrio, debemos construir una Tabla ICE. Cada fila representa una instancia (Inicial, Cambio, Equilibrio) y la completamos con la concentración o cambio de concentración ("x" para concentraciones desconocidas). Como inicialmente no hay productos, la reacción se desplazará hacia la derecha para alcanzar el equilibrio.

A + B ⇄ C + D

I 1 1 0 0

C -x -x +x +x

E 1-x 1-x x x

La constante de equilibrio, Kc, es:

$Kc = 5 = \frac{[C][D]}{[A][B]} = \frac{x^{2} }{(1-x)^{2} } \\\sqrt{5} = x/1-x\\x = 0.69$

Las concentraciones en el equilibrio son:

$[A] = [B] = 1-x = 1-0.69 = 0.31 M\\[C] = [D] = x = 0.69 M$

Puedes aprender más sobre equilibrio químico aquí: brainly.com/question/21632386

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3 years ago

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sleet_krkn [62]

Answer:

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3 years ago

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