A) solid 
b)liquid 
c)liquid 
d)gas
        
             
        
        
        
Answer:
3.64g
Explanation:
Given parameters: 
Mass of NH₃  = 18.1g 
Mass of Cu₂O  = 90.4g 
Unknown: 
Limiting reactant  = ? 
Mass of N₂ formed  = ? 
Solution: 
The reaction equation is given as: 
        Cu₂O + 2NH₃ → 6Cu + N₂ + 3H₂O 
The limiting reactant is the one in short supply in the reaction. Let us find the number of moles of the given species; 
   Number of moles =  
  
 Molar mass of Cu₂O = 2(63.6) + 16  = 143.2g/mol 
 Molar mass of NH₃  = 14 + 3(1) = 17g/mol 
Number of moles of Cu₂O =  = 0.13moles
   = 0.13moles 
Number of moles of NH₃   =  = 5.32moles
   = 5.32moles 
   From this reaction; 
        1 mole of  Cu₂O combines with 2 mole of NH₃
 So   0.13moles of  Cu₂O will combine with 0.13 x 2 mole of NH₃
                                               = 0.26moles of NH₃
Therefore, Cu₂O is the limiting reactant. Ammonia is in excess; 
 Mass of N₂; 
    Mass = number of moles x molar mass
     1 mole of Cu₂O  will produce 1 mole of N₂ 
     0.13 mole of Cu₂O  will produce 0.13 mole of N₂
     Mass  = 0.13 x (2 x 14) = 3.64g
 
        
             
        
        
        
Answer:
the correct words to fill up the blank spaces are falls and money
Explanation:
.1. the expected return on money falls
.2. causing the demand for money to fall.
 
        
             
        
        
        
They push away from each other or repel due to the same charge they have.