Answer:
Explanation:
The principle applied is the Markovnikoff's rule which states that when hydrogen chloride adds to a double bond, the hydrogen atoms join to the carbon that already has the most hydrogen atoms bonded to it. The rule wa postulated by a russian chemist known as Vladimir Markovnikoff.
In the markovnikoff's rule, there are sveral conditions that must be met, one of them is that no free radicals must be involved.
The reaction and the structure of the product is as shown in the attachment.
Answer:
The empirical formula is ZnO2
Explanation:
What is the empirical formula for a compound which contains 67.1% zinc and the rest is oxygen?
Step 1: Data given
Suppose the compound has a mass of 100.0 grams
A compound contains:
67.1 % Zinc = 67.1 grams
100 - 67.1 = 32.9 % oxygen = 32.9 grams
Molar mass of Zinc = 65.38 g/mol
Molar mass of O = 16 g/mol
Step 2: Calculate moles of Zinc
Suppose the compound is 100 grams
Moles Zn = 67. 10 grams / 65.38 g/mol
Moles Zn = 1.026 moles
Step 3: Calculate moles of O
Moles O = 32.90 grams / 16.00 g/mol
Moles O = 2.056 moles
Step 4: Calculate mol ratio
We divide by the smallest amount of moles
Zn: 1.026/1.026 = 1
O: 2.056/1.026 = 2
The empirical formula is ZnO2
To control this we can calculate the % Zinc for 1 mol
65.38 / (65.38+2*16) = 0.67.1 = 67.2 %
The enthalpy for the reaction : ΔH = -132
<h3>Further explanation</h3>
Given
Reaction and the enthalpy
Required
the enthalpy
Solution
Hess Law
Reaction 1 reverse :
A + B = G + C ΔH = -277
Reactions 2 and 3 remain the same (unchanged)
C + F = A ΔH = 303
D = B + H ΔH = -158
Add up all the reactions and remove the same compound from two different sides
D + F = G + H ΔH = -132
Answer:
7.28
Explanation:
-log(5.2x10^-8) = 7.28
- Hope that helped! Please let me know if you need further explanation.
Answer:
We say that the solution is unsaturated.
Explanation:
If the salt solubility is 36 g in 0.1 L of water then we can dissolve 360 g of salt in 1 L of water.
Because the solution contains 200 g of salt in 1 L of water, the solution is unsaturated because more salt can be added until we reach the saturation point.
We call the solution dilute when we compare the concentration of a solution with the concentration of another solution, but here we do not compare different solutions.