Answer:
Anita did not make the track team this year, and she feels really disappointed and upset. What question would most likely redirect her thinking and provide a solution?
Why did this terrible thing happen to me?
What other sports can I try this spring?
Why does everything I attempt go wrong?
Why did Karen get on the team but I didn't?
Answer - What other sports can I try this spring?
Explanation:
Failures and successes are part of our daily lives as humans. It can be very challenging for one to accept his or her failures and bring oneself above it.
when failure occur, the best way to reverse the negative impacts it brings is to move forward and decide on what next to do.
The actions that must be taken in the processes should be quite productive enough to bring back the results one desired.
When the effects of failures prove irreversible, one would then give the mind a diversion and help his or herself think their way though the failure that was encountered.
Answer:

Explanation:
Hello,
In this case, the chemical reaction is:

Thus, we first identify the limiting reactant by computing the yielded moles of water by both of the reactants:

In such a way, since HBr yields less water than cadmium hydroxide, we infer that HBr is the limiting one, therefore, the yielded mass of water are:

Regards.
First M stands for Molarity which is (moles of solute) / (Liters of solution). we also know that moles = (mass) / (molar mass). so we can form some equations here. We know:
Molarity (M) = moles (mol) / Liters (L)
moles (mol) = (mass) / (molar mass)
we can substitute the (mass) / (molar mass) for (moles) and get:
M = [(mass) / (molar mass)] / Liters
we can now isolate mass and get
M * Liters * molar mass = mass
now we need to find the molar mass of CaCl2 which is 110.98 g/mol
plug the values in and get
.350M * 6.5L * 110.98 g/mol = mass
mass = 252.4795g however the 6.5L has only 2 sig figs so i would say
mass CaCl2 = 2.5 * 10 ^2 g
When energy transforms into mass, the amount of energy does not remain the same. When mass transforms into energy, the amount of energy also does not remain the same. However, the amount of matter and energy remains the same. ... You would weigh much less on the Moon because it is only about one-sixth the mass of Earth. So the answer is D
Answer is: <span>the empirical formula of the hydrocarbon is CH</span>₂.<span>
Chemical reaction: C</span>ₓHₐ + O₂ → xC + a/2H₂O.<span>
m(CO</span>₂) = 33.01 g.
n(CO₂) = m(CO₂) ÷ M(CO₂).
n(CO₂) = 33.01 g ÷ 44.01 g/mol.
n(CO₂) = n(C) = 0.75 mol.
m(H₂O) = 13.52 g.
n(H₂O) = 13.52 g ÷ 18 g/mol.
n(H₂O) = 0.75 mol.
n(H) = 2 · n(H₂O) = 1.5 mol.
n(C) : n(H) = 0.75 mol : 1.5 mol /0.75 mol.
n(C) : n(H) = 1 : 2.