Answer:
190.4g
Explanation:
1.6mol of KBr (119.002g KBr/1 mol) = 190.4g
since you want to find grams, take the molar mass of KBr (119.002) per 1 mol and use it as your conversion factor (119.002g KBr/1 mol) which will then cancel out mols and leave you with grams.
According to the Avogadro’s law I mole of any substance contains = 6.023 x 1023
Number of molecules in one mole= 6.023 x 1023
Therefore number of molecules in 6.7 moles of AlCl3:
6.023x1023 molecules /1.0 mole * 6.7 mole
= 40.3541 x 1023 molecules
= 4.03541 x 1024 molecules
117 L. You can start by making a table to organize the information you are given. Then, you can use the formula PV/T=PV/T and plug in the numbers you have. You then solve for the missing volume. Remember that the initial pressure, temperature, and volume should be on one side of the equal sign, and the final pressure, volume, and temperature should be on the other side.