Answer:
For 6.0 eV
0.5 nm, 1.45*10^6 m/s, 6.17*10^10 m/s, 1.45*10^6 m/s
For 600 eV
1.26*10^-3 nm, 2.66*10^8 m/s, 3.37*10^8 m/s, 2.66*10^8 m/s
Explanation:
See attachment for calculation
Answer:
An Atom's individual speed will change as it collides with other atoms, so we have to use an average.
Explanation:
In a gas a single atoms does an assortment of things during its time in the gas—sometimes it collides with an other atom gaining a lot of speed, sometimes losing a lot of speed in the collision, and sometimes just moving freely. Therefore: the motion of one individual atom is unpredictable, and it cannot be representative of all the the atoms in a gas, which is why we must average over all speeds of all atoms to find an average speed that allows us to calculate other quantities like temperature and pressure of the gas.
Hence, the second option <em>"an Atom's individual speed will change as it collides with other atoms, so we have to use an average" </em>stands correct.
Answer:
A. refraction of light waves
Explanation:
Refraction happens when light travels from one medium to another and changes speed and bends. This also causes objects to look different sizes and shapes when they are submerged in water.
Answer:
ε₂ =2.63 V
Explanation:
given,
M = 0.0034 H
I (t) = I₀ sin (ωt)
I (t) = 5.4 sin (143 t)
magnitude of the induced emf in the second coil
ε₂ =
ε₂ =
for maximum emf
cos (143 t) = 1
ε₂ =
ε₂ =2.63 V
Explanation:
Given that,
A girl pushes her little brother on his sled with a force of 200. N for 850. m
We need to find the work done by the force of friction acting on the sled. The force of friction is 200 N
Net force = 200 N - 200 N = 0
Work done = 0
If force of friction is 300 N.
Net force = 300 N - 200 N = 100 N
The work done by a force is given by :
W = Fd
Put values,
W = 100 × 850
W = 85000 J
Hence, this is the required solution.