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Harrizon [31]
3 years ago
10

A wind turbine takes in energy from wind with the goal of converting it into electrical energy. Much of the wind energy is also

converted into the kinetic energy of the spinning turbine and heat lost to the air around it. If the goal of the turbine is to put out electric energy, what is the efficiency of the turbine?
Physics
2 answers:
Shalnov [3]3 years ago
6 0
German physicist  Albert Betz  (in 1919) demonstrated  that the highest efficiency you can achieve with a wind turbine is around 59%

We would have to analyze the design of an specific turbine to determine its efficiency, however it is unlikely to achieve 50% , as todays turbines have an average efficiency in the 20-35%

The answer would be around 25%

aivan3 [116]3 years ago
6 0

Answer:

Efficiency is ratio of output energy and input energy

Efficiency = \frac{Electrical \: energy}{Wind\: Energy}

Explanation:

Efficiency is defined as the output that we will get from a given machine for a given input of energy.

So here we know that input energy that we are getting from wind is in the form of electrical energy converted by the turbine and the input energy here is in the form of kinetic energy of wind or air molecules

so here this kinetic energy of wind will help to rotate the turbine due to which we will get the output electrical energy but in this whole process some of the wind energy is converted into heat due to frictional force between several components of turbine which shows our energy loss in this process

so efficiency is given by

Efficiency = \frac{Electrical \: energy}{Wind\: Energy}

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Gold's natural state has a definite shape and a definite volume. What is gold's natural state(s)?
zysi [14]

solid

Explanation:

because it has a definite shape and volume

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3 years ago
A bubble of air is rising up through the ocean. When it is at a depth of 20.0 m below the surface, where the temperature is 5.00
kotegsom [21]

Answer:

the volume is 0.253 cm³

Explanation:

The pressure underwater is related with the pressure in the surface through Pascal's law:

P(h)= Po + ρgh

where Po= pressure at a depth h under the surface (we assume = 1atm=101325 Pa) , ρ= density of water ,g= gravity , h= depth at h meters)

replacing values

P(h)= Po + ρgh = 101325 Pa + 1025 Kg/m³ * 9.8 m/s² * 20 m = 302225 Pa

Also assuming that the bubble behaves as an ideal gas

PV=nRT

where

P= absolute pressure, V= gas volume ,n= number of moles of gas, R= ideal gas constant , T= absolute temperature

therefore assuming that the mass of the bubble is the same ( it does not absorb other bubbles, divides into smaller ones or allow significant diffusion over its surface) we have

at the surface) PoVo=nRTo

at the depth h) PV=nRT

dividing both equations

(P/Po)(V/Vo)=(T/To)

or

V=Vo*(Po/P)(T/To) = 0.80 cm³ * (101325 Pa/302225 Pa)*(277K/293K) = 0.253 cm³

V = 0.253 cm³

3 0
3 years ago
What is dipersion of light
Sophie [7]

Answer:

The separation of visible light into its different colors is known as dispersion. It was mentioned in the Light and Color unit that each color is characteristic of a distinct wave frequency; and different frequencies of light waves will bend varying amounts upon passage through a prism

Explanation:

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2 years ago
Como se generan las ondas mecanicas y por que medios se propagan
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3 years ago
A charge of -3.30 nC is placed at the origin of an xy-coordinate system, and a charge of 2.05 nC is placed on the y axis at y =
Elis [28]

Answer:

F_{3h}=39065.298\times 10^9\ N attractive toward +x axis is the net horizontal force

F_v=80062.47\times 10^9 attractive toward +y axis is the net vertical force

Explanation:

Given:

  • charge at origin, Q_0=-3.35\times 10^{-6}\ C
  • magnitude of second charge, Q_2=2.05\times 10^{-6}\ C
  • magnitude of third charge, Q_3=5\times 10^{-6}\ C
  • position of second charge, (x_2,y_2)\equiv(0,4.35)\ cm
  • position of third charge, (x_3,y_3)\equiv(3.1,3.8)\ cm

<u>Now the distance between the charge at at origin and the second charge:</u>

d_2=\sqrt{(x_2-0)^2+(y_2-0)^2}

d_2=\sqrt{(0-0)^2+(4.35-0)^2}

d_2=0.0435\ m

<u>Now the distance between the charge at at origin and the third charge:</u>

d_3=\sqrt{(x_3-0)^2+(y_3-0)^2}

d_3=\sqrt{(3.1-0)^2+(3.8-0)^2}

d_3=0.04904\ m

<u>Now the force due to second charge:</u>

F_2=\frac{1}{4\pi.\epsilon_0} \times \frac{Q_0.Q_2}{d_2^2}

F_2=9\times 10^9\times \frac{3.3\times 2.05}{0.0435^2}

F_2=32175.98\times 10^9\ N attractive towards +y

<u>Now the force due to third charge:</u>

F_3=\frac{1}{4\pi.\epsilon_0} \times \frac{Q_0.Q_3}{d_3^2}

F_3=9\times 10^9\times \frac{3.3\times 5}{0.04904^2}

F_3=61748.38\times 10^9\ N attractive

<u>Now the its horizontal component:</u>

F_{3h}=\frac{3.1}{4.9} \times 61748.38\times 10^9

F_{3h}=39065.298\times 10^9\ N attractive toward +x axis

<u>Now the its vertical component:</u>

F_{3v}=\frac{3.8}{4.9} \times 61748.38\times 10^9

F_{3v}=47886.49\times 10^9\ N upwards attractive

Now the net vertical force:

F_v=F_{3v}+F_2

F_v=47886.49\times 10^9+32175.98\times 10^9

F_v=80062.47\times 10^9

3 0
3 years ago
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