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Nookie1986 [14]
3 years ago
15

Which of the following best describe the particles in a liquid.

Physics
1 answer:
VashaNatasha [74]3 years ago
4 0
A. fixed volume, changeable shape.
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Explain how to determine the volume of an irregularly shaped object such as a rock
alexira [117]
If you have no way to accurately measure all of the object's bumps and dimples, then the only way to measure its volume is by means of fluid displacement. 

-- Put some water into a graduated (marked) container, read the amount of water, drop the object into the container, and read the new volume in the container.  The volume of the object is the difference between the two readings.

-- Alternatively, stand an unmarked container in a large pan, and fill it to the brim. Slowly slowly lower the object into the unmarked container, while the pan catches the water that overflows from it.  When the object is completely down in the container, carefully remove the container from the pan, and measure the volume of the water in the pan.  It's equal to the volume of the object.
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3 years ago
1. ________________electricity is the type of electricity commonly used in homes and businesses throughout the world.
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Number 1 is letter A
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3 years ago
Planet A takes one year to go around the sun at a distance at a distance of one A U.. Planet B is three A U. from the sun. How m
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4 0
2 years ago
The y component of a vector is 36, and the angle between the vector and the x axis is 27 what is the magnitude of the vector
xz_007 [3.2K]

Answer:

Magnitude of Vector = 79.3

Explanation:

When a vector is resolved into its rectangular components, it forms two vector components. These components  are named as x-component and y-component, they are calculated by the following formulae:

x-component of vector = (Magnitude of Vector)(Cos θ)

y-component of vector = (Magnitude of Vector)(Sin θ)

where,

θ = angle of the vector with x-axis = 27°

Therefore, using the values in the equation of y-component, we get:

36 = (Magnitude of Vector)(Sin 27°)

Magnitude of Vector = 36/Sin 27°

<u>Magnitude of Vector = 79.3</u>

3 0
3 years ago
Suppose a yo-yo has a center shaft that has a 0.230 cm radius and that its string is being pulled.
Fofino [41]

Answer:

Part a)

\alpha = 782.6 rad/s^2

Part B)

\omega = 587 rad/s

Part c)

a_t = 24.3 m/s^2

Explanation:

Part a)

As we know that

a = R \alpha

so we will have

a = 1.80 m/s^2

R = 0.230 cm

\alpha = \frac{a}{R}

\alpha = \frac{1.80}{0.230 \times 10^{-2}}

\alpha = 782.6 rad/s^2

Part B)

Angular speed of the yo-yo

\omega = \alpha t

so we have

\omega = 782.6 \times 0.750

\omega = 587 rad/s

Part c)

Tangential acceleration is given as

a_t = R \alpha

a_t = (3.10 \times 10^{-2})(782.6)

a_t = 24.3 m/s^2

6 0
3 years ago
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