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uranmaximum [27]
2 years ago
9

What is the final volume (l) of a 10.0 l system that has the pressure quartered?

Chemistry
1 answer:
mihalych1998 [28]2 years ago
5 0
According to Boyle's Law, P1V1 = P2V2

where P1 and V1 are initial pressure and volume respectively. P2 and V2 are final pressure and volume receptively.

Given: P2 = 4 P1 and V1 = 10.0l

∴ V2 = 2.5 l

Answer: Final volume of system is 2.5 l


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they move around and eventually come and join to make a solid

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3 years ago
When the concentration of reactant molecules is increased
a_sh-v [17]

Complete question is;

When the concentrations of reactant molecules are increased, the rate of reaction increases. The best explanation for this phenomenon is that as the reactant concentration increases,

A)the average kinetic energy of molecules increases.

B)the frequency of molecular collisions increases.

C)the rate constant increases.

D)the activation energy increases.

E)the order of reaction increases.

Answer:

B) The frequency of molecular collisions increases.

Explanation:

When we increase number of reactant molecules, the effective collision between the reactant molecules will form a product which also increases. As a result, the overall rate of the reaction will also increase which means the frequency of the molecular collision will also increase as well.

Thus, the correct answer is Option B

6 0
2 years ago
Based on the ideal gas law, there is a simple equivalency that exists between the amount of gas and the volume it occupies. at s
nordsb [41]
<span>2.10 grams. The balanced equation for the reaction is CO + 2H2 ==> CH3OH The key thing to take from this equation is that it takes 2 hydrogen molecules per carbon monoxide molecule for this reaction. And since we've been given an equal number of molecules for each reactant, the limiting reactant will be hydrogen. We can effectively claim that we have 5.86/2 = 2.93 l of hydrogen and an excess of CO to consume all of the hydrogen. So the number of moles of hydrogen gas we have is: 2.93 l / 22.4 l/mol = 0.130803571 mol And since it takes 2 moles of hydrogen gas to make 1 mole of methanol, divide by 2, getting. 0.130803571 mol / 2 = 0.065401786 mol Now we just need to multiply the number of moles of methanol by its molar mass. First lookup the atomic weights involved. Atomic weight carbon = 12.0107 g/mol Atomic weight hydrogen = 1.00794 g/mol Atomic weight oxygen = 15.999 g/mol Molar mass CH3OH = 12.0107 + 4 * 1.00794 + 15.999 = 32.04146 g/mol So the mass produced is 32.04146 g/mol * 0.065401786 mol = 2.095568701 g And of course, properly round the answer to 3 significant digits, giving 2.10 grams.</span>
4 0
3 years ago
A solution is made using 148.5 g of dimethyl ether (MM = 46.07 g/mol) and 90.0 g of methanol (MM = 32.04 g/mol). What is the mol
Mariulka [41]

Answer:

0.534

Explanation:

Mole fraction can be calculated using the formula:

Mole fraction = number of moles of solute ÷ number of moles of solvent and solute (solution).

In this question, solute is dimethyl ether while the solvent is methanol.

Mole (n) = mass (M) ÷ molar mass (MM)

Mole of solute (dimethyl ether) = 148.5 ÷ 46.07

= 3.22moles.

Mole of solvent (methanol) = 90 ÷ 32.04

= 2.81moles.

Total moles of solute and solvent = 3.22 + 2.81 = 6.03moles.

Mole fraction of dimethyl ether = number of moles of dimethyl ether ÷ number of moles of solution (dimethyl ether + methanol)

Mole fraction = 3.22/6.03

= 0.534

6 0
3 years ago
State the order in which the ions associated with a
Shkiper50 [21]

State the order in which the ions associated with a compound composed of potassium and bromine would be written in the chemical formula and the compound name.

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