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3 years ago

Why do scientists often use bacteria to produce medicines?

Chemistry

2 answers:

Pani-rosa [81]3 years ago

8 0

Yes they do because its their job

JulijaS [17]3 years ago

7 0

Answer:

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Explanation:

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Calculate the number of moles of aluminum, sulfur, and oxygen atoms in 9.00 moles of aluminum sulfate, Al2(SO4)3.

vazorg [7]

The formula of aluminum sulfate is Al₂(SO₄)₃

Hence, 1 mole of Al₂(SO₄)₃ has 2 moles of Al, 3 moles of S and (4 x 3) or 12 moles of O

9 moles of Al₂(SO₄)₃ x (2 moles of Al/1 mole of Al₂(SO₄)₃) = 18 moles of Al

9 moles of Al₂(SO₄)₃ x (3 moles of S/1 mole of Al₂(SO₄)₃) = 27 moles of S

9 moles of Al₂(SO₄)₃ x (12 moles of O/1 mole of Al₂(SO₄)₃) = 108 moles of O

The number of moles of Al, S, and O atoms are 18, 27 and 108.

3 0

3 years ago

Complete end balance the reaction :copper plus hydrobromic acid

Reika [66]

Answer:

The correct answer is - 2Cu + 4HBr → 2H[CuBr2] + H2

Explanation:

Copper (Cu) and hydrobromic acid (HBr), which is a dissolved form of hydrogen bromide in the water, react and produce hydrogen dibromidocuprate (I) and hydrogen molecules.

The complete and balanced equation is -

2Cu + 4HBr → 2H[CuBr2] + H2

This reaction takes place in the medium of ester. Copper is in the suspension form in this reaction.

Thus, the correct answer is - 2Cu + 4HBr → 2H[CuBr2] + H2

5 0

3 years ago

A chef has decided that she will only cook in a way that does not alter the chemical make-up of food. Following these guidelines

valina [46]

She can prepare only C. milkshakes.

Toasting bread, scrambling eggs, and baking a cake all involve <em>chemical changes</em>.

7 0

3 years ago

Chemical equation of sodium carbonate on hydrochloric acid<br>

Novay_Z [31]

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Answer: Na2CO3 + 2 HCl → 2 NaCl + H2CO3

I hope this helped!

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5 0

3 years ago

Determine the oxidation states of the elements in the compounds listed. None of the oxygen-containing compounds are peroxides or

Ahat [919]

Answer :

Oxidation number or oxidation state : It represent the number of electrons lost or gained by the atoms of an element in a compound.

Oxidation numbers are generally written with the sign (+) and (-) first and then the magnitude.

Rules for Oxidation Numbers are :

The oxidation number of a free element is always zero.
The oxidation number of a monatomic ion equals the charge of the ion.
The oxidation number of Hydrogen (H) is +1, but it is -1 in when combined with less electronegative elements.
The oxidation number of oxygen (O) in compounds is usually -2.
The oxidation number of a Group 17 element in a binary compound is -1.
The sum of the oxidation numbers of all of the atoms in a neutral compound is zero.
The sum of the oxidation numbers in a polyatomic ion is equal to the charge of the ion.

Now we have to determine the oxidation state of the elements in the compound.

(a) $H_2SO_4$