The mass of glycerol to that would need to be combusted to heat 500.0g of water from 20.0°C to 100.0°C is; 9.32 grams.
We must establish the fact that energy is neither created nor destroyed.
Therefore, the amount of heat absorbed by water is equal to the amount of heat released by the combustion of glycerol.
Total heat absorbed by water, H(water) is;
Q(water) = m C (T2 - T1)
Q(water) = 500 × 4.184 × (100-20)
Q(water) = 167.36 kJ
Consequently, the quantity of heat evolved by the combustion of glycerol is;
Q(glycerol) = 167,360 J = n × ΔH°comb
where, n = no. of moles of glycerol.
167.36 kJ= n × 1654 kJ/mole
n = 167.36/1654
n = 0.1012 moles of glycerol.
Therefore, mass of glycerol combusted, m is;
m = n × Molar mass
m = 0.1012 × 92.09
m = 9.32 g.
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times concentration OH-