Answer:
8.5 inches and 34 inches
Step-by-step explanation:
Area of the square = 72.25
side² = 72.25
side = \sqrt{72.25}
Side = 8.5 in
Perimeter = 4 × side
Perimeter = 4 × 8.5 in
Perimeter = 34 in
Answer:
Step-by-step explanation:
Measures of angles are,
m∠A = (2x)°
m∠B = (x + 14)°
m∠C = (x - 38)°
By triangle sum theorem,
m∠A + m∠B + m∠C = 180°
2x + (x + 14) + (x - 38) = 180
(2x + x + x) + (14 - 38) = 180
4x - 24 = 180
4x = 204
x = 51
m∠A = 2(51)° = 102°
m∠B = (51 + 14)° = 65°
m∠C = (51 - 38)° = 13°
Answer:
the blank number is 23
Step-by-step explanation:
8, 15, 27, x, 20
common ratio, r= T2÷ T1= T3÷ T2
= 15 ÷ 8 =27÷ 15
= 1.8 = 1.8
20 ÷ x = x ÷ 27
( cross multiply,)
x²= 540
x =√540
x = 23.24
x = 23
Responder:
10 (2ny- (x-y))
Explicación paso a paso:
Dada la expresión 10ny-10x + 10ny + 10y, para simplificar la expresión, se deben seguir los siguientes pasos;
Paso 1; Separa la expresión en términos similares
= 10ny-10x + 10ny + 10y
= (10ny + 10ny) - (10x + 10y)
Paso 2: Factoriza los valores comunes en ambos paréntesis
10ny (1 + 1) - 10 (x-y)
= 10ny (2) - 10 (x-y)
= 20ny - 10 (x-y)
Factoriza nuestro valor común en ambos términos:
= 10 (2ny- (x-y))
XZ ≅ EG and YZ ≅ FG is enough to make triangles to be congruent by HL. Option b is correct.
Two triangles ΔXYZ and ΔEFG, are given with Y and F are right angles.
Condition to be determined that proves triangles to be congruent by HL.
<h3>What is HL of triangle?</h3>
HL implies the hypotenuse and leg pair of the right-angle triangle.
Here, two right-angle triangles ΔXYZ and ΔEFG are congruent by HL only if their hypotenuse and one leg are equal, i.e. XZ ≅ EG and YZ ≅ FG respectively.
Thus, XZ ≅ EG and YZ ≅ FG are enough to make triangles congruent by HL.
Learn more about HL here:
brainly.com/question/3914939
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In ΔXYZ and ΔEFG, angles Y and F are right angles. Which set of congruence criteria would be enough to establish that the two triangles are congruent by HL?
A.
XZ ≅ EG and ∠X ≅ ∠E
B.
XZ ≅ EG and YZ ≅ FG
C.
XZ ≅ FG and ∠X ≅ ∠E
D.
XY ≅ EF and YZ ≅ FG
