All categories

4 years ago

¿para que se utilizan los métodos de fraccionamiento de fases?

1 answer:

5 0

Answer: What are phase fractionation methods used for? well They apply to the prefractionation of the sample to obtain less complex protein mixtures for an easier analysis; they are also used as a means to evidence specific proteins or protein classes otherwise impossible to detect.

Explanation: in spanish /

Se aplican al prefraccionamiento de la muestra para obtener mezclas de proteínas menos complejas para un análisis más fácil; también se utilizan como un medio para evidenciar proteínas específicas o clases de proteínas que de otro modo serían imposibles de detectar.

You might be interested in

ose you has aniline as your unknown. What kind of solid derivative would be suitable to synthesize for aniline

gayaneshka [121]

Answer:

Amides are suitable to synthesize aniline

Explanation:

Amide are basically used to synthesize aniline.

The chemical formula of Aniline is C6H5NH2 while that of Amide is RCONH2

Amide are solids that can be easily converted to amines.

4 0

3 years ago

An ion has 38 protons, 36 electrons, and 40 neutrons, what us the elements symbol

Alexxandr [17]

Answer:

<h2>Strontium - Sr.</h2>

Explanation:

<h2>PLEASE MARK ME BRAINLIEST AND FOLLOW ME BRAINLIEST AND FOLLOW ME LOTS OF LOVE FROM MY HEART'AND SOUL DARLING TEJASWINI SINHA HERE ❤️</h2>

5 0

3 years ago

Read 2 more answers

A sample of mercury has a mass of 607.0 lb and a volume of 0.717 ft. What is its specific gravity? Number SG= What are the units

stepan [7]

Answer:

Specific gravity of mercury is 13.56 and it is an unit-less quantity.

Explanation:

Mass of the mercury = m = 607.0 lb = 275330.344 g

1 lb = 453.592 g

Volume of the mercury = v = $0.717 ft^3=20,303.18 mL$

$1 ft^3 = 28316.847 mL$

Density of the mercury = d= $\frac{m}{v}=\frac{275330.344 g}{20,303.18 mL}$

d = 13.56 g/mL

Specific gravity of substance = Density of substance ÷ Density of water

$S.G=\frac{d}{1 g/mL}$

Specific gravity of mercury :

$S.G=\frac{13.56 g/mL}{1 g/mL}=13.56$ (unit-less quantity)

5 0

4 years ago

This is an impossible formula. Pretend it is real.

guapka [62]

There are eight moles of oxygen atoms in 1 mole of $Mn_{9}(ClO_{4}) _{2}$ .

<h3>What is the number of moles of oxygen atoms?</h3>

We know that a compound is composed of atoms. The atoms that make up the molecule are chemically combined. It is usual that the number of atoms in the compound would correspond with the chemical formula.

Now we have the compound $Mn_{9}(ClO_{4}) _{2}$ . In one mole of the compound we have;

9 Moles of manganese atom
2 moles of chlorine atom
8 moles of oxygen atom

Thus, there are eight moles of oxygen atoms in 1 mole of $Mn_{9}(ClO_{4}) _{2}$ .

Learn more about atoms;brainly.com/question/1566330

#SPJ1

7 0

2 years ago

1. When frequency increases energy:

liraira [26]

B

When frequency increases, as does the energy, but wavelength decreases. It also works vise versa; if wavelength were to increase, its frequency and energy will decrease.

8 0

3 years ago