All categories

3 years ago

What is the chemical formula of iron (II) sulfide would be: (EO S = +2 and EO Fe = +2). please

Chemistry

1 answer:

Anni [7]3 years ago

7 0

Answer:

FeS

Explanation:

The reason why their is no subscripts is because as put in the question, the charges are equivalent. As you can see, +2 and -2 equal each other out.

Note: S has a charge of -2, not +2. (Look at oxidation rules.)

You might be interested in

A 8L sample of gas at 250 K is cooled to 75 K. What is the volume of the gas after it is cooled?

Stells [14]

$by \: Charles'\: law: \: \\ \frac{v_{1}}{t_{1}} = \frac{v_{2}}{t_{2}} \\$

Where v is the volume(in L) and t is the temperature(in °K)

$\frac{8}{250} = \frac{v_{2}}{75} \\\\4/5 =v_2/3 \\\\\boxed{v_{2} = \frac{12}{5}}\\\\\\\huge{=2.5 l}$

7 0

2 years ago

Explain which material is likely to slow the flow of electrical charges the most? *

babunello [35]

Answer:

The material which is likely to slow the flow of electric charges the most is PVC plastic ‾ \text{\underline{PVC plastic}} PVC plastic.

Explanation:

brainlist please

6 0

2 years ago

Read 2 more answers

Titanium and chlorine react to form titanium(IV) chloride, like this:

leva [86]

Answer:

the value of equilibrium constant for the reaction is 8.5 * 10⁷

Explanation:

Ti(s) + 2 Cl₂(g) ⇄ TiCl₄(l)

equilibrium constant Kc = $\frac{1}{[Cl_2]^2}$

Given that,

We are given:

Equilibrium amount of titanium = 2.93 g

Equilibrium amount of titanium tetrachloride = 2.02 g

Equilibrium amount of chlorine gas = 1.67 g

We calculate the No of mole = mass / molar mass

mass of chlorine gas = 1.67 g

Molar mass of chlorine gas = 71 g/mol

mole of chlorine = 1.67 / 71

= 7.0L

Concentration of chlorine is = no of mole / volume

= 0.024 / 7

= 3.43 * 10⁻³M

equilibrium constant Kc = $\frac{1}{[Cl_2]^2}$

= $\frac{1}{[3.43 * 10^-^3]^2}$

= 8.5 * 10⁷

4 0

3 years ago

Which of the following changes to a system WILL NOT result in an increase in the system’s pressure?

Sophie [7]

Answer:

B. All the rest raise P.

Explanation:

6 0

3 years ago

Assume the molality of isoborneol in your product is 0.275 mol/kg. What is the melting point of your impure sample given that th

aliina [53]

Answer:

168°C is the melting point of your impure sample.

Explanation:

Melting point of pure camphor= T =179°C

Melting point of sample = $T_f$ = ?

Depression in freezing point = $\Delta T_f$

Depression in freezing point is also given by formula:

$\Delta T_f=i\times K_f\times m$

$K_f$ = The freezing point depression constant

m = molality of the sample = 0.275 mol/kg

i = van't Hoff factor

We have: $K_f$ = 40°C kg/mol

i = 1 ( non electrolyte)

$\Delta T_f=1\times 40^oC kg/mol\times 0.275 mol/kg$

$\Delta T_f=11^oC$

$\Delta T_f=T- T_f$

$T_f=T- \Delta T_f=179^oC-11^oC=168^oC$

168°C is the melting point of your impure sample.

4 0

3 years ago