Q=mc(deltaT) Q is the amount of energy which you are looking for M is the mass which you can find C is the specific heat of water which is 4.18 J/gC DeltaT is the change in temperature which you can find.
To find the mass, first you must know that the density of water is 1g/mL, meaning that 200 mL has a mass of 200 g. This means that to find the total mass (m in the equation) all you need to do is add the mass of water and NaOH.
200 g + 2.535 g=202.535 g.
To find deltaT you would need to take the final temperature minus the initial temperature.
27.8C-24.2C=3.6C
Then these values can be substituted into the equation:
q=(202.635g)(4.18J/gC)(3.6C) Q=3049.25 J
Technically this should be rounded off to 1 significant figure (200 mL only had 1), but ignoring signficiant figure rules this should be correct. Also, sometimes other units like calories or kJ may be asked for, meaning that a conversion or alternate c value would be used.
<span>a. 3.1 calories in heat were released by the burning candy bar sample
b. The energy value of the sample was 3.1 Cal/g
c.The total caloric content of the candy bar is 232.5 Calories, derived by multiplying the total mass of the candy bar by its fuel value per gram</span>
