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tangare [24]
3 years ago
8

Does sodium have a positive or negative charge after ionization?

Chemistry
1 answer:
melomori [17]3 years ago
3 0
After ionization, sodium gains a net positive charge cuz sodium loses its 1 valence electron to gain the nearest stable octet which is neon{Ne}. Hope it helps
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A solution containing a mixture of metal cations was treated with dilute HCl and no precipitate formed. Next, H2S was bubbled th
erica [24]

Answer:

Explanation:

  Ions which will  be definitely  absent -

Ag⁺ , Hg₂⁺ , Pb⁺², because their chlorides are insoluble in water.

Ba⁺² ,Ca⁺² because their carbonates are insoluble in water,

Ions which will be definitely present  

Cu⁺² , Pb⁺² . Hg⁺² , Sb⁺³ , Sn⁺² , because their sulphides are insoluble at pH = 8.

For the rest nothing can be said.

 

5 0
3 years ago
Calculate the ΔG°rxn using the following information at 298K. 2 HNO3(aq) + NO(g) → 3 NO2(g) + H2O(l) ΔG°rxn = ? ΔH°f (kJ/mol) -2
Mkey [24]

Answer:

ΔG°rxn = +50.8 kJ/mol

Explanation:

It is possible to obtain ΔG°rxn of a reaction at certain temperature from ΔH°rxn and S°rxn, thus:

<em>ΔG°rxn = ΔH°rxn - T×S°rxn (1)</em>

In the reaction:

2 HNO3(aq) + NO(g) → 3 NO2(g) + H2O(l)

ΔH°rxn = 3×ΔHfNO2 + ΔHfH2O - (2×ΔHfHNO3 + ΔHfNO)

ΔH°rxn = 3×33.2kJ/mol + (-285.8kJ/mol) - (2×-207.0kJ/mol + 91.3kJ/mol)}

ΔH°rxn = 136.5kJ/mol

And S°:

S°rxn = 3×S°NO2 + S°H2O - (2×S°HNO3 + S°NO)

ΔH°rxn = 3×0.2401kJ/molK + (0.0700kJ/molK) - (2×0.146kJ/molK + 0.2108kJ/molK)

ΔH°rxn = 0.2875kJ/molK

And replacing in (1) at 298K:

ΔG°rxn = 136.5kJ/mol - 298K×0.2875kJ/molK

<em>ΔG°rxn = +50.8 kJ/mol</em>

<em />

7 0
3 years ago
Read 2 more answers
Suppose you are a food chemist working for a company that makes and manufactures soda. Your job is to create a new soft drink wi
Mekhanik [1.2K]

Answer:

The answer to your question is given after the questions so I just explain how to get it.

Explanation:

a)

Get the molecular weight of Phosphoric acid

        H₃PO₄ =  (3 x 1) + (31 x 1) + (16 x 4)

                    = 3 + 31 + 64

                    = 98 g

         98 g -----------------  1 mol

      0.045 g ---------------   x

          x = (0.045 x 1) / 98

          x = 0.045 / 98

          x = 0.00046 moles or 4.6 x 10 ⁻⁴

b)

Molarity = \frac{moles}{volume}

Molarity = \frac{0.00046}{0.35}

Molarity = 0.0013 or 1.31 x 10⁻³

c)

Formula            C₁V₁ = C₂V₂

                              V₁ = C₂V₂ / C₁

Substitution

                              V₁ = (0.0013)(1) / 0.01

Simplification and result

                              V₁ = 0.0013 / 0.1

                              V₁ = 0.13 l = 130 ml            

7 0
3 years ago
If 500ml of H₂ gas at 600mmHg and 400ml of CO₂ gas at 700mmHg are mixed in a 1 lit vessel, find the total pressure of mixture of
seraphim [82]

Answer:

Total pressure increased

Explanation:

When gas C is added in the vessel then number of mole increases and number of collision depends on the number of molecules present in the vessel and on adding gas C ,mole also increases hence  number of collision increases therefore pressure also increases because number of collision increases.

Total pressure increases.

6 0
2 years ago
Compute the number of grams(g) of lead in 22.5 moles of lead.
iogann1982 [59]

Answer:

4662 in grams

Explanation:

hope this helps :).

7 0
2 years ago
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