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yaroslaw [1]
3 years ago
8

Which type of cell is larger

Chemistry
1 answer:
Karo-lina-s [1.5K]3 years ago
5 0

Answer: eukaryotic cell

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Which example best shows that the chemistry of water is helpful to plants
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<span>Water's polarity causes cohesion that pulls other water molecules up through a plant.</span>
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4 years ago
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predict an element that would react with water as lithium (Li), sodium (Na), and potassium (K) did. explain.
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Any of the other alkali metals not mentioned (I.e. rubidium, caesium or francium). They are all group one metals meaning that they contain one valence (outer shell) electron so they will have similar properties. Francium is the most reactive alkali metal while lithium is the least reactive (if you’d like me to explain that let me know :) )
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3 years ago
A chemist adds 26.5g of ammonium chloride to 10g of sodium hydroxide, which follows the reaction below. Assuming the reaction go
4vir4ik [10]

Answer :  The amount of reactant left in excess is 13.1075 grams.

Explanation : Given,

Mass of NH_4Cl = 26.5 g

Mass of NaOH = 10 g

Molar mass of NH_4Cl = 53.5 g/mole

Molar mass of NaOH = 40 g/mole

First we have to calculate the moles of NH_4Cl and NaOH.

\text{Moles of }NH_4Cl=\frac{\text{Mass of }NH_4Cl}{\text{Molar mass of }NH_4Cl}=\frac{26.5g}{53.5g/mole}=0.495moles

\text{Moles of }NaOH=\frac{\text{Mass of }NaOH}{\text{Molar mass of }NaOH}=\frac{10g}{40g/mole}=0.25moles

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

NH_4Cl+NaOH\rightarrow NH_4OH+NaCl

From the balanced reaction we conclude that

As, 1 mole of NaOH react with 1 mole of NH_4Cl

So, 0.25 moles of NaOH react with 0.25 moles of NH_4Cl

From this we conclude that, NH_4Cl is an excess reagent because the given moles are greater than the required moles and NaOH is a limiting reagent and it limits the formation of product.

Moles of remaining excess reactant = 0.495 - 0.25 = 0.245 moles

Now we have to calculate the mass of NH_4Cl.

\text{Mass of }NH_4Cl=\text{Moles of }NH_4Cl\times \text{Molar mass of }NH_4Cl

\text{Mass of }NH_4Cl=(0.245mole)\times (53.5g/mole)=13.1075g

Therefore, the amount of reactant left in excess is 13.1075 grams.

5 0
3 years ago
Find the mass, in grams, of 5.00*10^23 molecules of F2
Westkost [7]

Answer:   31.55 g

Explanation:

- The mass number of Fluoride atom (F) = 18.99 g/mol, so mass number of         fluorine gas (F2) = 37.98 g/mol.

-  1 mole of (F2) [which has 37.98 g/mol] contains Avogadro’s number of molecules (6.02×10^23 molecules),

   so   1 mole of (F2) with 37.98 g/mol →  6.02×10^23 molecules.

- Using cross multiplication,  

                               37.98 g/mol of (F2)        →       6.02 ×10^23 molecules

                                                       ?              →        5.00 ×10^23 molecules

Hence the mass of 5.00×10^23 molecules of F2 = (37.98 × 5.00 × 10^23) / 6.02 ×10^23 = 31.55 g..


7 0
4 years ago
Which state(s) of matter will flow and take the shape of its container?
WARRIOR [948]
Liquids flow and take the shape of their containers.
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3 years ago
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