The velocity of a 485 kg elevator that has 5900 J of energy is 108.6 m/s
<h3>What is the velocity of the elevator?</h3>
A moving elevator possesses kinetic energy due to its motion.
The velocity of the elevator is calculated from the formula of kinetic energy.
The kinetic energy formula is : Kinetic energy = ¹/₂mv₂
The velocity, v = √2KE/m
v = √(2 * 5900/485)
v = 108.6 m/s
In conclusion, the velocity of the elevator is calculated from the kinetic energy and mass of the elevator.
Learn more about velocity and kinetic energy at: brainly.com/question/25959744
#SPJ1
The standard cell potential of a cell made of theoretical metals ma/ma2+ and mb/mb2+ is to be determined. We are given their reduction potentials:
-0.19 v for A
-0.85 v for B
To solve for the standard cell potential, examine the reaction and
the standard cell potential for this case is (-0.19- (-0.85)) v = -0.66 v<span />
Answer:
40.0 L.
Explanation:
- We can use the general law of ideal gas: <em>PV = nRT.</em>
where, P is the pressure of the gas in atm.
V is the volume of the gas in L.
n is the no. of moles of the gas in mol.
R is the general gas constant,
T is the temperature of the gas in K.
- If P and T are constant, and have different values of n and V:
<em>(V₁n₂) = (V₂n₁).</em>
V₁ = 50.0 L, n₁ = 2.0 moles,
V₂ = ??? L, n₂ = 2.0 mol - 0.4 mol = 1.6 mol.
∴ V₂ = (V₁n₂)/(n₁) = (50.0 L)(1.6 mol)/(2.0 mol) = 40.0 L.
Unicellular had one cell and multicellular has more than one
