Answer:
304.19 g
Explanation:
M(H2) = 2*1 = 2 g/mol
54.1 g H2 * 1 mol H2/2gH2 = 27.05 mol H2
3H2 + N2 ------> 2NH3
from reaction 3 mol 2 mol
given 27.05 mol x mol
x = 27.05*2/3 = 18.03 mol NH3
M(NH3) = 14 +3*1 = 17 g/mol
18.03 mol NH3 * 17 g NH3/ 1 mol NH3 ≈ 307 g
Closeet answer is 304.19 g.
From the coefficients of the equation, we know that for every 3 moles of water consumed, 1 mole of diphosphorus trioxide is consumed.
This means we need to find the mass of 0.75 moles of diphosphorus trioxide.
- The atomic mass of phosphorous is 30.973761998 g/mol.
- The atomic mass of oxygen is 15.9994 g/mol.
So, the formula mass of diphosphorus trioxide is:
- 2(30.973761998)+3(15.9994)=109.945723996 g/mol.
Thus, 0.75 moles have a mass of:
- 0.75(109.945723996), which is about 82.5 g (to 3 sf)
Answer:
When a chemical reaction occur, new substances are formed. The physical and chemical properties of new substances are different from initial substance.
Explanation:
Chemical change:
The changes, that occur due to change in the composition of a substance and result in a different compound is known as chemical change.
These changes are irreversible.
These changes occur due to chemical reactions.
These may not be observed with naked eye.
Examples:
Combustion of fuel or wood: that oil or wood convert into energy, CO2 and ash in case of wood .
Boiling of egg: that change the chemical composition of protein in the egg.
Physical change:
The changes that occur only due to change in shape or form but their chemical or internal composition remain unchanged.
These changes were reversible.
They have same chemical property.
These changes can be observed with naked eye.
Examples:
Water converting to Ice.
Water converting to gas.
In this water molecule remain the same only they rearrange themselves that change its state of mater not composition.
The amount of heat required to change the sample from ice at -45.0°C to liquid water at 75.0°C is 83.8 kJ.
<h3>
Quantity heat required to convert the ice to liquid</h3>
The total quantity of heat required is calculated as follows;
q(tot) = q1(to ice) + q2(fusion of ice) + q3(liquid)
q(tot) = mcΔθ₁ + mΔHf + mcΔθ₂
q(tot) = (100)(4.2)(0 - -45) + (334)(100) + (100)(4.2)(75 - 0)
q(tot) = 18,900 J + 33,400 J + 31,500 J
q(tot) = 18.900 kJ + 33.400 kJ + 31.500 kJ
q(tot) = 83,800 J = 83.8 kJ
Thus, the amount of heat required to change the sample from ice at -45.0°C to liquid water at 75.0°C is 83.8 kJ.
Learn more about quantity of heat here: brainly.com/question/13439286
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