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NARA [144]
3 years ago
8

Name two elements, compounds and mixtures that are essential for living organisms. Also write why are they essential?​

Chemistry
2 answers:
Butoxors [25]3 years ago
8 0

Answer:

Elements-

  1. Oxygen is essential for living organisms to survive.
  2. Carbon dioxide is essential for the survival, growth and reproduction of living things. Plants obtain carbon from the atmosphere in the form of carbon dioxide, which they need for photosynthesis. They convert inorganic carbon into organic carbon in the form of sugar and starch, which they add to their tissues.

Compounds-

  1. Water is essential for living organisms to stay hydrated.
  2. Carbohydrate and protein- These compound are used to form new cells and tissues and to repair.

Mixtures-

  1. Blood is very much important for the transportation of oxygen in living organisms.
  2. Blood plasma is an example of a homogeneous mixture. This is a colourless fluid that holds the blood cells in suspension. It makes up a little more than half of the volume of human blood.

svlad2 [7]3 years ago
5 0

elements:

calcium : for strong bones

Iron : maintaining haemoglobin for metabolism

compunds

sodium chloride : to maintain blood pressure and other life processes

Adenosine Triphosphate: for metabolism, to maintain rate of inhalation and exhalation of oxygen and to supply energy

Mixture:

I) gasoline : used as fuel

ii) cement : used in construction

You might be interested in
Identify one type of noncovalent bond present in each solid.
NeX [460]

Answer:

Explanation:

The question is not complete, the cmplete question is:

Identify one type of noncovalent bond present in each solid.

1) Table salt (NaCl)                2) Graphite (repeating)

a. hydrogen bonds

b. ionic interactions

c. van der Waals interactions

d. hydrophobic interactions

Answer:

1) Table salt

b. ionic interactions

Ionic bond are formed between atoms with incomplete outermost shell. Some atoms add electrons to their outermost shell to make the shell complete hence making it a negative ion while some atoms loses their electron to make the outermost shell complete becoming a positive ion. In NaCl, sodium (Na) has 1 electron in its outermost shell which it transfers to Cl which has 7 electrons in the outermost shell. Hence after the bonding the outermost shell of the atoms become complete.

2) Graphite

c. Van Der Waals interaction

Van der waal  forces are weak interaction between molecules that exist between close atoms. Carbon atoms in graphite planes have covalent bond, these graphite planes are known as graphenes. Bonds between graphenes are very weak and are van der waals forces.

7 0
3 years ago
A weather balloon is filled with helium that occupies a volume of 5.57 104 L at 0.995 atm and 32.0°C. After it is released, it r
Alchen [17]

6.52 × 10⁴ L. (3 sig. fig.)

<h3>Explanation</h3>

Helium is a noble gas. The interaction between two helium molecules is rather weak, which makes the gas rather "ideal."

Consider the ideal gas law:

P\cdot V = n\cdot R\cdot T,

where

  • P is the pressure of the gas,
  • V is the volume of the gas,
  • n is the number of gas particles in the gas,
  • R is the ideal gas constant, and
  • T is the absolute temperature of the gas in degrees Kelvins.

The question is asking for the final volume V of the gas. Rearrange the ideal gas equation for volume:

V = \dfrac{n \cdot R \cdot T}{P}.

Both the temperature of the gas, T, and the pressure on the gas changed in this process. To find the new volume of the gas, change one variable at a time.

Start with the absolute temperature of the gas:

  • T_0 = (32.0 + 273.15) \;\text{K} = 305.15\;\text{K},
  • T_1 = (-14.5 + 273.15) \;\text{K} = 258.65\;\text{K}.

The volume of the gas is proportional to its temperature if both n and P stay constant.

  • n won't change unless the balloon leaks, and
  • consider P to be constant, for calculations that include T.

V_1 = V_0 \cdot \dfrac{T_1}{T_2} = 5.57\times 10^{4}\;\text{L}\times \dfrac{258.65\;\textbf{K}}{305.15\;\textbf{K}} = 4.72122\times 10^{4}\;\text{L}.

Now, keep the temperature at T_1 =258.65\;\text{K} and change the pressure on the gas:

  • P_1 = 0.995\;\text{atm},
  • P_2 = 0.720\;\text{atm}.

The volume of the gas is proportional to the reciprocal of its absolute temperature \dfrac{1}{T} if both n and T stays constant. In other words,

V_2 = V_1 \cdot\dfrac{\dfrac{1}{P_2}}{\dfrac{1}{P_1}} = V_1\cdot\dfrac{P_1}{P_2} = 4.72122\times 10^{4}\;\text{L}\times\dfrac{0.995\;\text{atm}}{0.720\;\text{atm}}=6.52\times 10^{4}\;\text{L}

(3 sig. fig. as in the question.).

See if you get the same result if you hold T constant, change P, and then move on to change T.

6 0
3 years ago
What are the various ways in which an atom of an element can achieve the noble gas configuration ? ​
azamat

Answer:

<h3><em>Atoms attain noble gas configuration </em><em> by obtaining or donating and sharing of electrons present in their outermost shell.</em><em> </em></h3>
7 0
3 years ago
In which direction did the following equilibrium shift when it was placed in the hot water bath? [CoCl4] 2- (aq) + 6H2O (l) ⇌ [C
djyliett [7]

Answer:

The equilibrium position will shift towards the lefthand side.

Explanation:

[CoCl4] 2- (aq) + 6H2O (l) ⇌ [Co(H2O)6] 2+ (aq) + 4 Cl- (aq)

The equation written above in exothermic as written. That is, the forward reaction is exothermic. The equilibrium position is observable by monitoring the colour change of the solution. At the left hand side, the solution is blue but at the right hand side the solution is pink. Addition of heat (in a hot water bath) will shift the equilibrium towards the left hand side, that is formation of more [CoCl4] 2- making the solution to appear blue in colour.

3 0
3 years ago
Which is the correct number of moles of NO that is produced from 13.2 moles of oxygen
Oksanka [162]
<h3>Answer:</h3>

10.6 mol NO

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[RxN - Balanced] 4NH₃ + 5O₂ → 4NO + 6H₂O

[Given] 13.2 mol O₂

<u>Step 2: Identify Conversions</u>

[RxN] 5 mol O₂ → 4 mol NO

<u>Step 3: Stoich</u>

  1. [DA] Set up:                                                                                                     \displaystyle 13.2 \ mol \ O_2(\frac{4 \ mol \ NO}{5 \ mol \ O_2})
  2. [DA] Multiply/Divide [Cancel out units]:                                                         \displaystyle 10.56 \ mol \ NO

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

10.56 mol NO ≈ 10.6 mol NO

5 0
3 years ago
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