The specific gravity of a sample is the ratio of the density of the sample with respect to one standard sample. The standard sample used in specific gravity calculation is water whose density is 1 g/mL. The solution having specific gravity 1.30 is the density of the sample that is 1.30 g/mL. Thus the weight of the 30 mL sample is (30×1.30) = 39 g.
Now the mass of the 10 mL of water is 10 g as density of water is 10 g/mL. Thus after addition the total mass of the solution is (39 + 10) = 49g and the volume is (30 + 10) = 40 mL. Thus the density of the mixture will be
g/mL. Thus the specific gravity of the mixed sample will be 1.225 g/mL.
Answer:
I think it will option D hope it helps
Answer:
0.1056 mole
Explanation:
As Sally knows that the charge on the metal ion is n = +2

In that compartment ![$[M^{n+}]=[m^{2+}]=8.279 \ M$](https://tex.z-dn.net/?f=%24%5BM%5E%7Bn%2B%7D%5D%3D%5Bm%5E%7B2%2B%7D%5D%3D8.279%20%5C%20M%24)
The volume of the
taken in that compartment = 6.380 mL
So, the number of moles of 
= 52.82 m mol
= 0.05280 mol

But n = 2
Therefore, moles of
= 2 x moles of 
= 2 x 0.05282
= 0.1056 mole
The temperature of vinegar does increase the rate of reaction according to the collision theory.
Hope this answers your question!