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3 years ago

15

How to classify hemicetal and acetal

1 answer:

kumpel [21]3 years ago

3 0

You might have meant hemiacetal, not hemicetal.
Acetals contain two –OR groups, one –R group and a –H atom. In hemiacetals, one of the –OR groups in acetals is replaced by a –OH group<span>.
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Indicate how the concentration of each species in the chemical equation will change to reestablish equilibrium after changing th

Viktor [21]

Explanation:

Since this is an equilibrium problem, we apply le chatelier principle. This principle states that whenever a system at equilibrium is disturbed due to change in several factors, it would move in a way to annul such change.

C2H4(g) + Cl2 ⇔ 2C2H4Cl2(g)

When the concentration of C2H4 is increased, there is more reactant sin the system. In order to annul this change, the equilibrium position will shift to the right favoring product formation.

When the concentration of C2H4Cl2 is increased, there is more product in the system. To annul this change, the equilibrium position will shift to the left, favoring reactant formation.

7 0

4 years ago

Non-electrolyte = A, 10.6 grams, dissolved in solvent B, 740 grams, the boiling point of the solution is higher than the boiling

Thepotemich [5.8K]

Answer:

2.1 °C/m

Explanation:

Hello, for this exercise, consider the formula:

$T_{solution}-T{solvent}=K_bm_solute$

Considering that the difference in the temperature is 0.284°C, and the given molality by:

$m_{solute}=\frac{10.6g\frac{1mol}{106g}}{740g*\frac{1kg}{1000g} } \\m_{solute}=0.135m$

Now, solving for $K_b$ , we get:

$K_b=\frac{0.284C}{0.135m}\\K_b=2.1 C/m$

Best regards.

8 0

3 years ago

In a particular electroplating process, the metal being plated has a +4 charge. If 861.8 C of charge pass through the cell, how

Xelga [282]

Answer: $2.2326\times 10^{-3}$ moles

Explanation:

We are given:

Moles of electron = 1 mole

According to mole concept:

1 mole of an atom contains $6.022\times 10^{23}$ number of particles.

We know that:

Charge on 1 electron = $1.6\times 10^{-19}C$

Charge on 1 mole of electrons = $1.6\times 10^{-19}\times 6.022\times 10^{23}=96500C$

The metal being plated has a +4 charge, thus the equation will be:

$M^{4+}+4e^-\rightarrow M$

$4\times 96500C$ of electricity deposits = 1 mole of metal

Thus 861.8 C of electricity deposits = $\frac{1}{4\times 96500}\times 861.8=2.2326\times 10^{-3}$ moles of metal

Thus $2.2326\times 10^{-3}$ moles of metal should be plated

3 0

3 years ago

Carbon dioxide, when it is at -145 degreesC has a density of 2.54 g/L. What is the pressure in torr??

Black_prince [1.1K]

Answer: The pressure in torr is 461 torr

Explanation:

To calculate the relation of density and molar mass of a compound, we use the ideal gas equation:

PV=nRT

P = pressure

V = Volume

n = number of moles

R = gas constant = 0.0821 Latm/Kmol

T = temperature = $-145^0C=(273-145)K=128K$

Number of moles (n) can be written as:

$n=\frac{m}{M}$

where, m = given mass

M = molar mass = 44 g/mol

$PV=\frac{m}{M}RT\\\\PM=\frac{m}{V}RT$

where,

$\frac{m}{V}=d$

where d = density = 2.54 g/L

The relation becomes:

PM=dRT

$P=\frac{dRT}{M}$

$P=\frac{2.54\times 0.0821\times 128}{44}=0.607atm$

$P=461torr$ (760torr=1atm)

Thus the pressure in torr is 461 torr

5 0

3 years ago

HELPPP MEEE ASAPP!!!

SVEN [57.7K]

Answer:

the answer is B 200%

Explanation:

cause its the second column

4 0

3 years ago