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Deffense [45]
3 years ago
15

How to classify hemicetal and acetal

Chemistry
1 answer:
kumpel [21]3 years ago
3 0
You might have meant hemiacetal, not hemicetal.
Acetals contain two –OR groups, one –R group and a –H atom. In hemiacetals, one of the –OR groups in acetals is replaced by a –OH group<span>.
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ra1l [238]

Answer:

b. . the element symbol

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3 years ago
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Consider the peptide with amino acid sequence NICE. Write the full name and the three-letter abbreviations of the amino acids in
kifflom [539]

Answer:

I don't know what is that

8 0
3 years ago
How much did bottled water grow between 2015 and 2016?​
Solnce55 [7]

Answer:

The International Bottled Water Association (IBWA), Alexandria, Va., and Beverage Marketing Corporation (BMC), New York, recently released 2015 bottled water statistics showing that Americans' consumption of bottled water increased by 7.9 percent and bottled water sales were up 8.9 percent from the previous year.

Explanation:

7 0
3 years ago
What mass in grams of fructose is contained in 325 mL of a 1.5 M fructose solution
STALIN [3.7K]

87.75 g of fructose

Explanation:

molar concentration = number of moles / volume (L)

number of moles = molar concentration × volume

number of moles of fructose = 1.5 × 0.325

number of moles of fructose = 0.4875 moles

number of moles = mass / molar weight

mass =  number of moles × molar weight

mass of fructose = 0.4875 × 180

mass of fructose = 87.75 g

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molar concentration

brainly.com/question/13971392

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3 0
3 years ago
Determine the mass of each of t he following:
EastWind [94]

Explanation:

Mass of compounds = Moles of compound × Molecular mass of compound

a) Moles of LiCl = 2.345 mol

Molecular mass of LiCl = 42.5 g/mol

Mass of 2.345 moles of LiCl = 2.345 mol × 42.5 g/mol = 99.6625 g

b) Moles of acetylene = 0.0872 mol

Molecular mass of acetylene= 26 g/mol

Mass of 0.0872 moles acetylene= 0.0872 mol × 26 g/mol = 2.2672 g

c) Moles of sodium carbonate= 3.3\times 10^{-2}mol

Molecular mass of sodium carbonate= 106 g/mol

Mass of  3.3\times 10^{-2}mol sodium carbonate

=  3.3\times 10^{-2}mol\times 106 g/mol= 3.498 g

d) Moles of fructose = 1.23\times 10^3 mol

Molecular mass fructose= 180 g/mol

Mass of  1.23\times 10^3 mol fructose

=  1.23\times 10^3mol\times 180 g/mol = 221,400 g

e) Moles of  FeSO_4(H_2O)_7=0.5758 mol

Molecular mass of FeSO_4(H_2O)_7 =278 g/mol

Mass of  1.23\times 10^3 mol fructose

=  0.5758 mol\times 278 g/mol= 160.0724 g

3 0
3 years ago
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