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miskamm [114]
3 years ago
11

Compare the distance between the molecules of a gas in a very small container with the distance between the molecules of the sam

e gas in a very large container. Explain your answer
Chemistry
1 answer:
kvv77 [185]3 years ago
6 0
Gases take the shape of their container. When you have a large container, the spaces between molecules (particles) can be further apart than if they were close together. In small containers, the particles are forced to be closer together, or compressed.

Think of it like a pep rally in a gym v.s. a classroom. In the gym, everyone has a bit of wiggle room. With the same number of people in a classroom, everyone would need to be packed in there. This can also explain why a smaller pot over boils from steam before a larger one does, even if the amount of water is the same.
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Glycerol boils at a high temperature than water. What does this indicate about the attractive forces of glycerol?
forsale [732]
Glycerol attractive forces are great than water. The harder to break, the more energy is needed.
5 0
3 years ago
A city water district wants to encourage local businesses and homeowners to landscape with drought-tolerant plants. After disapp
tino4ka555 [31]

Answer:

the complete question is found in the attachment

Explanation:

the complete explanation is found in the attachment

3 0
3 years ago
Molarity to percent by mass. Convert 1.672 mol/L MgCl2(aq) solution to percent by mass of MgCl2 in the solution. The solution de
nignag [31]

Answer:

\%m/m=14\%

Explanation:

Hello!

In this case, since the molarity of magnesium chloride (molar mass = 95.211 g/mol) is 1.672 mol/L and we know the density of the solution, we can first compute the concentration in g/L as shown below:

[MgCl_2]=1.672\frac{molMgCl_2}{L}*\frac{95.211gMgCl_2}{1molMgCl_2}=159.2\frac{gMgCl_2}{L}

Next, since the density of the solution is 1.137 g/mL, we can compute the concentration in g/g as shown below:

[MgCl_2]=159.2\frac{gMgCl_2}{L}*\frac{1L}{1000mL}*\frac{1mL}{1.137g}=0.14

Which is also the by-mass fraction and in percent it turns out:

\%m/m=0.14*100\%\\\\\%m/m=14\%

Best regards!

6 0
3 years ago
Hurry please!
Pani-rosa [81]

Answer : The mass of of water present in the jar is, 298.79 g

Solution : Given,

Mass of barium nitrate = 27 g

The solubility of barium nitrate at 20^oC is 9.02 gram per 100 ml of water.

As, 9.02 gram of barium nitrate present in 100 ml of water

So, 27 gram of barium nitrate present in \frac{27g}{9.02g}\times 100ml=299.33ml of water

The volume of water is 299.33 ml.

As we know that the density of water at 20^oC is 0.9982 g/ml

Now we have to calculate the mass of water.

\text{Mass of water}=\text{Density of water}\times \text{Volume of water}

\text{Mass of water}=(0.9982g/ml)\times (299.33ml)=298.79g

Therefore, the mass of of water present in the jar is, 298.79 g

5 0
3 years ago
If 585.24 Joules of heat are added to 53.2 grams of water at 24.15oC, what will the new temp. be?
spayn [35]
E = mct
Energy = (mass) x (specific heat capacity of water) x (change in temp)

585.24 = 53.2 x 4.2 x (X-24.15)


585.24 divided by 53.2 divided by 4.2 = X - 24.15

2.62 = X - 24.15

X= 26.77degrees C

(Specific heat capacity for water is 4.2 but is different for other liquids)
3 0
4 years ago
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