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3 years ago

Compare fission and fusion reactions and explain the difference between their energy input and output.

2 answers:

8 0

Both the two are atomic responses that deliver vitality, however, the applications are not the same. Parting is the part of a substantial, flimsy core into two lighter cores, and the combination is the procedure where two light cores join together discharging tremendous measures of vitality.

sertanlavr [38]3 years ago

7 0

Answer :

Nuclear fusion : It is defined as a process which involves the conversion of two small nuclei to form a heavy nuclei and some amount of energy is also releases.

Nuclear fission : It is defined as a process which involves the conversion of a heavier nuclei (which is an unstable nuclei) into two or more small nuclei (which is a stable nuclei) and a large amount of energy is also releases.

The difference between the nuclear fusion and nuclear fission is that, the energy is given in the nuclear fusion reaction but the energy is releases in the nuclear fission reaction.

In nuclear fusion, a small amount of energy is released but in nuclear fission, more amount of energy is released.

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An ionic bond is best described as

LekaFEV [45]

The answer would be B the transfer of electrons from one atom to another

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4 years ago

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The substitution reaction of toluene with Br2 can, in principle, lead to the formation of three isomeric bromotoluene products.

GREYUIT [131]

Answer:

See explanation and image attached

Explanation:

Aromatic hydrocarbons undergo electrophillic substitution. Usually, substituted benzene is more or less reactive to electrophillic substitution compared to unsubstituted benzene.

Substituents on the benzene ring tend to direct the incoming electrophile during electrophillic substititution. The presence of the -CH3 group on toluene directs the incoming Br electrophile to the ortho/para position.

Where the incoming electrphile E is Bromine, we can see that in the ortho/ para product, the electron pushing -CH3 stabilizes the resonance structure formed and increases electron density at the ortho/para position via resonance compared to the meta product as we can see from the image attached. Hence, the ortho and para products predominate over meta products.

Image credit: Chemistry steps

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3 years ago

Use the ideal gas law to calculate the pressure in atmospheres of 0.21 mol of helium (He) at 16°C & occupying 2.53 L. You mu

chubhunter [2.5K]

Answer:

The answer to your question is 2.32 atm

Explanation:

Data

P = ?

n = 0.214

V = 2.53 L

T = 61°C

R = 0.082 atm L/mol°K

Formula

PV = nTR

solve for P

P = nRT/V

Process

1.- Calculate the temperature in K

°K = °C + 273

°K = 61 + 273

= 334

2.- Substitution

P = (0.214 x 0.082 x 334) / 2.53

3.- Simplification

P = 5.86/2.53

4.- Result

P = 2.32 atm

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3 years ago

On the basis of le chatelier's principle explain why ag2co3 dissolves when hno3 is added

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The reaction is an equilibrium represented by the equation

<span>Ag2CO3(s) + 2 HNO3(aq) <----> 2 AgNO3(aq) + H2O(l) + CO2(g) </span>

From the <span>Le Chatelier's Principle which </span>states that changing a factor such as concentration, temperature, or pressure of a reaction at equilibrium will cause the reaction to shift in the direction that counteracts the effect of that change.
Therefore; the CO2 produced starts escaping and the concentration and pressure of CO2 drops. The system responds by trying to increase the concentration and pressure of CO2 by producing more. This means more and more Ag2CO3 will dissolve due to reaction with the acid, HNO3.
This continues until one of the reactants is exhausted.

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3 years ago

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Trava [24]

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