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krek1111 [17]
3 years ago
12

Potassium forms ions with a charge of +1 (K+). Iodine forms ions with a charge of -1. Selenium forms ions with a charge of -2 (S

e2-). Imagine that Potassium ions and Selenide ions combine to form Potassium Selenide. What numbers would be in the place of X and Y in: KXSeY
Chemistry
1 answer:
olga55 [171]3 years ago
5 0

It is given that the charge on potassium is +1 i.e. Potassium is a cation, K⁺ and the charge on selenium is given as -2, i.e. selenium is an anion, Se²⁻

The two ions are shown to combine to form a molecule: KXSeY where X and Y correspond to the proportions in which the two atoms combine.

Since the molecule is neutral, the positive and negative charges need to be balanced. This is possible only if 2 units of K⁺ combines with 1 unit of Se²⁻.

Therefore, the formula would be K₂Se

X = 2 and Y = 1



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Explanation : Given,

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\Delta T_f=i\times K_f\times m\\\\T^o-T_s=i\times K_f\times\frac{\text{Mass of urea}}{\text{Molar mass of urea}\times \text{Mass of solvent in Kg}}

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i = Van't Hoff factor = 1 (for urea non-electrolyte)

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m = molality

Now put all the given values in this formula, we get

-10.1^oC-T_s=1\times (5.32^oC/m)\times \frac{29.82g}{60.06g/mol\times 0.500kg}

T_s=-15.4^oC

Therefore, the freezing point of a solution is -15.4^oC

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