They were going at a velocity 4.07m/s
<u>Explanation:</u>
Distance s =5 m
initial velocity u= 0.8 m/s
Acceleration a =1.6m/s2
We have to calculate the velocity with which they were going afterwards i.e final velocity.
Use the equation of motion
They were going with a velocity 4.07 m/s afterwards.
The answer is the first one
Use KE= 1/2mv^2
So...
50,000=(.5)(1,000)v^2
50,000=500 x v^2
Divide 500 on both sides
100 = v^2
Square root both sides to get rid of v^2
Therefore v = 10 m/s
Approximately 0.4373 seconds
Speed of sound at 20 degree C is roughly 343 meters/second
Speed of light = 3x10^8 or 300,000,000 meters/second
at 150.0 feet away you set it up as:
150.0/343 - 150/3x10^8
150.0/343 = 0.43731778
150/3x10^8 = 5x10^-7 or 0.0000005
Subtract 0.43731778 - 0.0000005
Answer is 0.43731728
Rounding would be approx. 0.4373
