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Anna11 [10]
3 years ago
8

4. Shirley Bored sits in her seat in the English classroom. The force of gravity on Earth pulls

Physics
1 answer:
Sedbober [7]3 years ago
4 0

Answer:

600 N upward

Explanation:

According to Newton's third law, for every action their is an equal and opposite reaction. The equal and opposite reaction to a downward force of magnitude 600 N is an upward force of magnitude 600 N

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Objects have a tendency to resist changing their motion. This property is called: *
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Answer:

The answer your looking for is option 2 - Inertia

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4. A car, initially traveling east with a speed of
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Answer:

150 m

Explanation:

Given,

u=5m/s

a=2m/s2

t=10s

v=?

s=?

Now,

v=u+at

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=5+20

=25m/s

So,

s=u+v/2×t

=5+25/2×10

=30/2×10

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How many types of quarks are there?<br> a. 2<br> b. 4<br> c. 6<br> d. 8
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calculate earths velocity of approach toward the sun when earth in its orbit is at an extremum of the latus rectum through the s
IceJOKER [234]

Answer:

Hello your question is incomplete below is the complete question

Calculate Earths velocity of approach toward the sun when earth in its orbit is at an extremum of the latus rectum through the sun, Take the eccentricity of Earth's orbit to be 1/60 and its Semimajor axis to be 93,000,000

answer : V = 1.624* 10^-5 m/s

Explanation:

First we have to calculate the value of a

a = 93 * 10^6 mile/m  * 1609.344 m

  = 149.668 * 10^8 m

next we will express the distance between the earth and the sun

r = \frac{a(1-E^2)}{1+Ecos\beta }   --------- (1)

a = 149.668 * 10^8

E (eccentricity ) = ( 1/60 )^2

\beta = 90°

input the given values into equation 1 above

r = 149.626 * 10^9 m

next calculate the Earths velocity of approach towards the sun using this equation

v^2 = \frac{4\pi^2 }{r_{c} }   ------ (2)

Note :

Rc = 149.626 * 10^9 m

equation 2 becomes

(V^2 = (\frac{4\pi^{2}  }{149.626*10^9})

therefore : V = 1.624* 10^-5 m/s

4 0
3 years ago
Help with 3 and check the other ones please :(
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I don’t know what your talking about. ?!?!?!?
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2 years ago
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