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vovangra [49]
3 years ago
12

Which statement describes a difference between electromagnetic and mechanical waves? A. Mechanical waves do not transfer energy,

but electromagnetic waves do. B. Mechanical waves cannot be longitudinal, but electromagnetic waves can. C. Electromagnetic waves cannot move particles, but mechanical waves can. D. Electromagnetic waves do not require a medium, but mechanical waves do
Physics
1 answer:
Natasha_Volkova [10]3 years ago
8 0
The answer is D.

Mechanical waves need a medium to travel, for example, sound is a mechanical wave. You are able to hear other people because the sound wave is travelling trough a fluid -air-. If you were to be in space -vacuum- you would not be able to hear anything. 

The most well known example of an electromagnetic wave is light. As you may have noticed, we're able to get the light from the Sun to Earth; clearly light -electromagnetic wave- is able to travel in vacuum/space (i.e., without a medium).
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What type of energy moves through wires
jarptica [38.1K]

Answer:

current electricity

Explanation:

have a nice day

8 0
3 years ago
If a gas has a gage pressure of 156 kPa, its absolute pressure is approximately
patriot [66]
The correct answer for the question that is being presented above is this one: "256 kpa." <span>If a gas has a gage pressure of 156 kPa, its absolute pressure is approximately 256 kpa. </span>Gauge pressure (GP) is 0 at atmospheric pressure (AP). Absolute pressure= GP + AP. Since atmospheric pressure is ca. 100 kpa; 100 + 156 is 256 kpa.
5 0
3 years ago
Read 2 more answers
Millikan is doing his oil drop experiment. He has a droplet with radius 1.6 µm suspended motionless in a uniform electric field
swat32

Answer:

The charge on the droplet is 3.106\times10^{-16}\ C.

Yes, quantization of charge is obeyed within experimental error.

Explanation:

Given that,

Radius = 1.6μm

Electric field = 46 N/C

Density of oil = 0.085 g/cm³

We need to calculate the charge on the droplet

Using formula of force

F= qE

mg=qE

V\times\rho\times g=qE

q=\dfrac{V\times\rho}{E}

q=\dfrac{\dfrac{4}{3}\pi\times r^3\times\rho\times g}{E}

Put the value into the formula

q=\dfrac{\dfrac{4}{3}\times\pi\times(1.6\times10^{-6})^3\times85\times9.8}{46}

q=3.106\times10^{-16}\ C

We need to calculate the quantization of charge

Using formula of quantization

n = \dfrac{q}{e}

Put the value into the formula

n=\dfrac{3.106\times10^{-16}}{1.6\times10^{-19}}

n=1941.25

Yes, quantization of charge is obeyed within experimental error.

Hence, The charge on the droplet is 3.106\times10^{-16}\ C.

Yes, quantization of charge is obeyed within experimental error.

7 0
3 years ago
Read 2 more answers
4) An electron moving along the +x-axis enters a magnetic field. If the electron experiences a magnetic deflection in the -y dir
Maurinko [17]

Answer:

B) along the -z-axis.

Explanation:

  • According to the Fleming's left hand rule we know that when a positive charge moves with velocity v perpendicular to the direction of magnetic field the it experiences a magnetic force perpendicular to the the plane in which the velocity vector and the magnetic field vector lies.
  • As a result all the three vector are mutually perpendicular in such a case.
  • Here as per given condition we have a negative charge moving along x-axis which experiences the deflection in -y direction so the magnetic field will be along the negative z axis i.e. into the screen.
3 0
4 years ago
Read 2 more answers
The the figure shows a famous roller coaster ride. You can ignore friction. If the roller coaster leaves Point Q from rest, what
ch4aika [34]

Answer:

22 m/s

Explanation:

PEf +KEf =PE0 +KE0 →PE0 −PEf =KEf

−mgΔy= 1 mv2 →v= −2gΔy = −2(9.8 m/s2)(−25 m)=22 m/s

3 0
3 years ago
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