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4 years ago

Y= -8x-3 x+y=7 is (3,4) a solution of the system

Mathematics

1 answer:

fgiga [73]4 years ago

3 0

Answer:

Step-by-step explanation:

The given point does not satisfy the first equation.

y = -8(3) -3 = -27

4 ≠ -27 . . . . . the first equation is not satisfied.

(3, 4) is not a solution

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Plz answer this, will give brainliest answer

RideAnS [48]

Answer:

Similar - Yes

Similarity Statement - cdef ~ qrst

Scale factor - 3/4

Step-by-step explanation:

Hope this helps :)

8 0

2 years ago

Please answer this correctly without making mistakes

madreJ [45]

Answer:

4 - pound bag of pears for $14.08

Step-by-step explanation:

To find out which is the better deal, we have to simplify it.

By dividing $14.08 by 4, this gives us the amount of $ each pound costs, which is $3.52.

Now let's find out the amount of $ each pound costs for the 94- ounce bag of pears for $22.56.

First, we need to convert from ounces (oz) to pounds (lbs).

There are 16 ounces in one pound, and we have 94 ounces. So, 94/16 = 5.875 pounds. So there are 5.875 lbs in the $22.56 bag. Now we need to find the amount of $ each pound costs. So we divide $22.56 by 5.875 and we get $3.84.

$3.52 < $3.84 (this is the amount of money each pound of pears cost for each bag). The first bag is cheaper per pound, so they should buy the first one (which is the 4 pound bag btw).

8 0

3 years ago

Many elementary school students in a school district currently have ear infections. A random sample of children in two different

Marta_Voda [28]

Answer:

Step-by-step explanation:

The summary of the given data includes;

sample size for the first school $n_1$ = 42

sample size for the second school $n_2$ = 34

so 16 out of 42 i.e $x_1$ = 16 and 18 out of 34 i.e $x_2$ = 18 have ear infection.

the proportion of students with ear infection Is as follows:

$\hat p_1 = \dfrac{16}{42}$ = 0.38095

$\hat p_2 = \dfrac{18}{34}$ = 0.5294

Since this is a two tailed test , the null and the alternative hypothesis can be computed as :

$H_0 :p_1 -p_2 = 0 \\ \\ H_1 : p_1 - p_2 \neq 0$

level of significance ∝ = 0.05,

Using the table of standard normal distribution, the value of z that corresponds to the two-tailed probability 0.05 is 1.96. Thus, we will reject the null hypothesis if the value of the test statistics is less than -1.96 or more than 1.96.

The test statistics for the difference in proportion can be achieved by using a pooled sample proportion.

$\bar p = \dfrac{x_1 +x_2}{n_1 +n_2}$

$\bar p = \dfrac{16 +18}{42 +34}$

$\bar p = \dfrac{34}{76}$

$\bar p = 0.447368$

$\bar p + \bar q = 1 \\ \\ \bar q = 1 -\bar p \\ \\\bar q = 1 - 0.447368 \\ \\\bar q = 0.552632$

The pooled standard error can be computed by using the formula:

$S.E = \sqrt{ \dfrac{ \bar p \bar q}{ n_1} + \dfrac{\bar p \bar p}{n_2} }$

$S.E = \sqrt{ \dfrac{ 0.447368 * 0.552632}{ 42} + \dfrac{ 0.447368 * 0.447368}{34} }$

$S.E = \sqrt{ \dfrac{ 0.2472298726}{ 42} + \dfrac{ 0.2001381274}{34} }$

$S.E = \sqrt{ 0.01177284105}$

$S.E = 0.1085$

The test statistics is ;

$z = \dfrac{\hat p_1 - \hat p_2}{S.E}$

$z = \dfrac{0.38095- 0.5294}{0.1085}$

$z = \dfrac{-0.14845}{0.1085}$

z = - 1.368

Decision Rule: Since the test statistics is greater than the rejection region - 1.96 , we fail to reject the null hypothesis.

Conclusion: There is insufficient evidence to support the claim that a difference exists between the proportions of students who have ear infections at the two schools

5 0

3 years ago

A car enthusiast is interested in studying the relationship between the asking price of used cars and their age. Which is more n

AlexFokin [52]

Answer:

B.Car's price

3 0

3 years ago

What is the slope of this line?

sergiy2304 [10]

Answer: 2/1

Step-by-step explanation:

2/1 because you use rise/run which is moving up 2 units from (0,3) to (0,5) and then moving right 1 unit to (1,5)

8 0

2 years ago

Read 2 more answers