V^2-u^2=2as
v=final velocity=unkown
u=initial velocity=0 m/s, because freely falling
a=acceleration due to gravity=9.8 m/s^2
s=distance (here height) traveled=4.5m
therefore the final velocity,
v^2=2*9.8*4.5
v=<span>9.39m/s</span>
Interesante muy interesante
Pero no que estás diciendo???
Yes you got this buddy you're an A+ student
Do they give answer choices? or is it free write? i’ll help if you tell me!!
Answer:
Range will be 5707.364 m
Explanation:
We have given initial velocity of projectile u = 355 m/sec
Angle of projection = 68.4°
Acceleration due to gravity 
Horizontal range is given by 
It is given that range is shorten by 35.1%
So range will be