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Shtirlitz [24]
3 years ago
6

PLLLLLLLLLLZ HELP The virtual image of a lens is always on the same side of the lens as the object.

Physics
1 answer:
aniked [119]3 years ago
8 0

Answer:

true

Explanation:

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Calculate the constant acceleration a in g’s which the catapult of an aircraft carrier must provide to produce a launch velocity
goblinko [34]
The solution to the problem is as follows:

<span>First, I'd convert 188 mi/hr to ft/s. You should end up with about ~275.7 ft/s.
 
So now write down all the values you know:

Vfinal = 275.7 ft/s

Vinitial = 0 ft/s

distance = 299ft
</span>
<span>Now just plug in Vf, Vi and d to solve
</span>
<span>Vf^2 = Vi^2 + 2 a d 

</span><span>BTW: That will give you the acceleration in ft/s^2. You can convert that to "g"s by dividing it by 32 since 1 g is 32 ft/s^2.</span>
5 0
3 years ago
How does 'g' vary from place to place?​
r-ruslan [8.4K]

Explanation:

The acceleration g varies by about 1/2 of 1 percent with position on Earth's surface, from about 9.78 metres per second per second at the Equator to approximately 9.83 metres per second per second at the poles.

8 0
3 years ago
You are given three resistors with the following resistances: R1 = 6.32 Ω, R2 = 8.13 Ω, and R3 = 2.29 Ω. What is the largest equ
andreyandreev [35.5K]

Answer:

The largest equivalent resistance yu can build using these three resistors is a Serie Resistance with the value of R= 16.74 Ω

Explanation:

Adding Resistances in serie is the way to build de largest equivalent value possible.

Rt= R1+R2+R3

Rt= 6.32 + 8.13 + 2.29

Rt= 16.74Ω

5 0
3 years ago
What is acceleration?​
Kisachek [45]
Acceleration is the force of something moving, or acceleration can be how fast an object is going!
7 0
3 years ago
Read 2 more answers
The bell rings and a physics student heads to class. They stop to talk to a few friends. They slow
grin007 [14]

Answer:

420m

Explanation:

Given parameters:

Time  = 5minutes

Average speed  = 1.4m/s

Unknown:

Distance covered  = ?

Solution:

Speed is the rate of change of distance with time.

 Mathematically;

              Speed  = \frac{distance}{time}  

    Distance  = speed x time

 

Insert the parameters and solve;

   Convert the time to seconds;

              1 minute = 60s

               5 minute = 5  x 60 = 300s

So,

   Insert the parameters and find the distance;

     Distance  = 300 x 1.4  = 420m

3 0
3 years ago
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