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ale4655 [162]
3 years ago
15

Two football players with mass 75 kg and 100 kg run directly toward each other with speeds of 6 m/s and 8 m/s respectively. if t

hey grab each other as they collide, the combined speed of the two players just after the collision would be:
Physics
1 answer:
3241004551 [841]3 years ago
6 0

<u><em>heyaaaaa</em></u>

<u><em>Momentum before Pb = momentum after Pa</em></u>

Pb = 75*6 - 100*8 = -350kgm/s = Pa = (75+100)V where V is the velocity of the combined mass of the two players after the collision.

<u><em>Velocity has magnitude (speed) and direction. V = -350/175 = -2m/s </em></u>

So the two players are moving at 2m/s in the direction the 100kg player was moving before the collision.

<em><u>I arbitrarily chose the direction of the smaller player as positive so the opposite direction (of the larger player) had to be negative. </u></em>

hope it helpssss!!!!!!

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Answer:

Explanation:

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3. They propagate at different speed though a non vacuum media (non vacuum media affect the speed based on the wavelength)

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4 years ago
in which of the exercise and sports science do specialist study achievement motivation , arousal attribution and personality dev
Mekhanik [1.2K]

Sport and exercise psychology

Explanation:

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7 0
3 years ago
Um carro percorre um trecho de 450 km em escalar media do carro
Aleks04 [339]

Average speed of the car is defined as the ratio of total distance and total time

So here we will have

v_{avg} = \frac{distance}{time}

now we know that

distance = 450 km

time = 5 h

now from above equation we will have

v = \frac{450 km}{5 h} = 90 km/h

so the average speed will be 90 km/h

7 0
3 years ago
What is a cars acceleration in the direction of motion when velocity changes from 20. M/s to 60. M/s in 10. S
brilliants [131]

Answer:

Acceleration, a=4\ m/s^2

Explanation:

Given that,

Initial velocity, u = 20 m/s

Final velocity, v = 60 m/s

Time, t = 10 s

We need to find the acceleration of the car. It is equal to the change in velocity divided by time.

a=\dfrac{v-u}{t}\\\\a=\dfrac{60-20}{10}\\\\a=\dfrac{40}{10}\\\\a=4\ m/s^2

So, the acceleration of the car is 4\ m/s^2.

8 0
3 years ago
The figure shows the arrangement of master cylinder and slave cylinder of a part of braking system. The master cylinder piston,
Neko [114]

Answer:

a) 35 kPa

d) 140 N

c) 1) Increasing the brake fluid  pressure

2)  Increasing the slave piston surface area.

Explanation:

The parameters given are;

a) Force applied to the master cylinder piston = 28 N

Cross sectional area of the master cylinder piston = 8 cm² = 8 × 10⁻⁴ m²

The pressure P on the brake fluid is given by the formula for pressure as follows;

P= \dfrac{Applied \ force}{Area \over \ which \  force \ is \ applied} = \dfrac{28 \, N}{8 \times 10^{-4} \, m^2} = 35,000 \, N/m^2 = 35,000 \, Pa

The pressure on the brake fluid, P, produced by the master cylinder piston = 35,000 Pa = 35 kPa

b) Given that the area of the slave piston = 40 cm² = 0.004 m², we have from the formula for pressure, P;

P= \dfrac{Applied \ force}{Area \over \ which \  force \ is \ applied} = \dfrac{Applied \ force}{4 \times 10^{-3} \, m^2} = 35,000 \, N/m^2

Therefore;

Applied force on the slave piston = 4 × 10⁻³ m² × 35,000 N/m² = 140 N

c) The force, F produced by the slave cylinder piston is given by the relation;

F = Pressure × Area

Therefore, the two ways of increasing the force produced by the slave cylinder piston is as follows;

1) Increasing the pressure in the brake fluid by increasing the force exerted by the master cylinder piston

2) Increasing the surface area of the slave piston.

4 0
3 years ago
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