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2 years ago

Describe the relationship between the length and period of a pendulum in the language of direct proportions

Physics

1 answer:

Wittaler [7]2 years ago

3 0

The period of the pendulum is directly proportional to the square root of the length of the pendulum

Explanation:

The period of a simple pendulum is given by the equation

$T=2\pi \sqrt{\frac{L}{g}}$

where

T is the period

L is the length of the pendulum

g is the acceleration of gravity

From the equation, we see that when the length of the pendulum increases, the period of the pendulum increases as the square root of L, $T\propto \sqrt{L}$ . This means that

The period of the pendulum is directly proportional to the square root of the length of the pendulum

From the equation, we also notice that the period of a pendulum does not depend on its mass.

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__________ (marketing research) information is collected from questions (measurements) that are free from systematic or statisti

tatiyna

Answer: reliable

Explanation:

Reliable (marketing research) information is collected from questions (measurements) that are free from systematic or statistical error. An absence of systematic error implies that the respondents (i.e., the sampled people) who answer questions actually understand what the questions were asking.

3 0

2 years ago

The distance between two consecutive nodesof a standing wave is 20.9cm.Thehandgen-erating the pulses moves up and down throughac

irina1246 [14]

Answer:

Velocity, v = 0.239 m/s

Explanation:

Given that,

The distance between two consecutive nodes of a standing wave is 20.9 cm = 0.209 m

The hand generating the pulses moves up and down through a complete cycle 2.57 times every 4.47 s.

For a standing wave, the distance between two consecutive nodes is equal to half of the wavelength.

$\dfrac{\lambda}{2}=0.209\ m\\\\\lambda=0.418\ m$

Frequency is number of cycles per unit time.

$f=\dfrac{2.57}{4.47}\\\\f=0.574\ Hz$

Now we can find the velocity of the wave.

Velocity = frequency × wavelength

v = 0.574 × 0.418

v = 0.239 m/s

So, the velocity of the wave is 0.239 m/s.

4 0

2 years ago

Based on illustrations of magnetic field lines, where could an object be placed so it would not experience a magnetic force

tiny-mole [99]

<u>Halfway</u><u> between the like poles of two magnets, because the field lines bend away and do not enter this area.</u>

How does a magnetic field diagram show where the field is strongest?

The magnetic field lines do not ever cross.
The lines include arrowheads to indicate the direction of the force exerted by a magnetic north pole.
The closer the lines are to the poles, the stronger the magnetic field (thus the magnetic field from a bar magnet is highest closest to the poles).

Where is magnetic field the strongest and weakest on a magnet?

The bar magnet's magnetic field is strongest at its core and weakest between its two poles.
The magnetic field lines are densest immediately outside the bar magnet and least dense in the core.

Which two locations on the magnet would have the greatest attractive forces?

Inside the magnet itself, the field lines run from the south pole to the north pole.
The magnetic field is strongest in areas of greatest density of magnetic field lines, or areas of the greatest magnetic flux density.

Learn more about magnetic field

brainly.com/question/11514007

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4 0

1 year ago

At what speed, as a fraction of c , is a particle's total energy twice its rest energy

WINSTONCH [101]

The rest energy of a particle is
$E_0=m_0 c^2$
where $m_0$ is the rest mass of the particle and c is the speed of light.

The total energy of a relativistic particle is
$E=mc^2 = \frac{m_0 c^2}{ \sqrt{1- \frac{v^2}{c^2} } }$
where v is the speed of the particle.

We want the total energy of the particle to be twice its rest energy, so that
$E=2E_0$
which means:
$\frac{m_0c^2}{ \sqrt{1- \frac{v^2}{c^2} } }=2m_0 c^2$
$\frac{1}{ \sqrt{1- \frac{v^2}{c^2} } }=2$
From which we find the ratio between the speed of the particle v and the speed of light c:
$\frac{v}{c}= \sqrt{1- (\frac{1}{2})^2 } =0.87$
So, the particle should travel at 0.87c in order to have its total energy equal to twice its rest energy.

3 0

3 years ago

¿Qué energía cinética posee una pelota de tenis de 65 g que se sirve a una velocidad de 200 km / h?

vekshin1

Therefore, the kinetic energy of an object is proportional to the square of its velocity (speed). In other words, If there is a twofold increase in speed, the kinetic energy will increase by a factor of four. If there is a threefold increase in speed, the kinetic energy will increase by a factor of nine.

4 0

3 years ago