Question:
The question is incomplete. The mass and radius of the orbit was not added. Find below the remaining part of the question and the answer.
Rank from largest to smallest.
A) m=200 kg and L= 5000m
B) m=400 kg and L=2500m
C)m=100kg and L=2500m
D)m=100kg and L=10000m
E)m=800kg and L=5000m
F)m=300kg and L=7500m
Answer:
Fe > Ff > Fa = Fb = Fd > Fc
4*10^6 N > 2.25*10^6 > 1 *10^6 N = 1 *10^6 N = 1 *10^6 N > 0.25*10^6 N
Explanation:
The force experienced by the satellite is given by the formula;
Fc = kmL
where;
k = constant = 4π²/T²
m = mass of satellite
L = radius of orbit
Since, all the satellites complete the circular orbit in the same amount of time. The constant k does not affect the force value.
A) The force acting on satellite A from their rocket is given as follows:
Fa = kmL
Fa = 200 * 5000
= 1 *10^6 N
B) The force acting on satellite B from their rocket is given as follows:
Fb = kmL
=400 *2500
= 1*10^6 N
C) The force acting on satellite C from their rocket is given as follows:
Fc = kmL
= 100 *2500
= 0.25*10^6 N
D) The force acting on satellite D from their rocket is given as follows:
Fd = kmL
= 100 *10000
= 1*10^6 N
E) The force acting on satellite E from their rocket is given as follows:
Fe = kmL
= 800 *5000
= 4*10^6 N
F) The force acting on satellite F from their rocket is given as follows:
Ff = kmL
= 300 *7500
= 2.25*10^6 N
The ranking is given as:
Fe > Ff > Fa = Fb = Fd > Fc
4*10^6 N > 2.25*10^6 > 1 *10^6 N = 1 *10^6 N = 1 *10^6 N > 0.25*10^6 N
a)
The acceleration due to gravity at a certain location on Earth is given by
where
G is the gravitational constant
M is the Earth's mass
R is the Earth's radius
h is the altitude above the Earth's surface
At the top of Mt. Everest,
R = 6380 km =
With
(1)
At the Earth's surface,
R = 6380 km =
h = 0
g = ?
So
(2)
By doing the ratio (2)/(1), we find an expression for g in terms of g':
And therefore,
b) 519.3 N
The weight of an object near the Earth's surface is given by
where
m is the mass of the object
g is the acceleration of gravity at the object's location
In this problem,
m = 50 kg is the mass of the object
g' = 9.77 m/s^2 is the acceleration of gravity on top of Mt Everest
Susbtituting,
Answer:
your answer is 187=223-323=gang
Explanation:
The gravitational force between the Earth and the Moon is
Explanation:
The gravitational force between two objects is given by:
where
:
is the gravitational constant
m1, m2 are the masses of the two objects
r is the separation between them objects
In this problem, we are given:
(mass of the Moon)
(mass of the Earth)
(distance between Earth and Moon)
Substituting into the formula, we find the force:
Learn more about gravitational force:
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