Answer:
Player II should remove 14 coins from the heap of size 22.
Step-by-step explanation:
To properly answer this this question, we need to understand the principle and what it is exactly is being asked.
This question revolves round a game of Nim
What is a game of Nim: This is a strategic mathematical game whereby, two opposing sides or opponent take turns taking away objects from a load or piles. On each turn, a player remove at least an object and may remove any number of objects provided they all come from the same heap/pile.
Now, referring back to the question, we should first understand that:
22₂ = 1 0 1 1 0
19₂= 1 0 0 1 1
14₂= 0 1 1 1 0
11₂= 0 1 0 1 1
and also that the “bit sums” are all even, so this is a balanced game.
However, after Player I removes 6 coins from the heap of size 19, Player II should remove 14 coins from the heap of size 22.
Answer:
I put in y = 2-x. I believe that was the equation you asked a table for. If it is another equation please tell me or just download or look up Desmos. Desmos helps create graphs and tables. I hope this helps. Have a great rest of your day!
Answer: x=58
Step-by-step explanation:
We know that the entire angle equals 360 degrees
Let’s subtract 293 from 360
360- 293 = 67
Then let’s subtract 44 from 67 to get (x-35)
67 - 44 = 23
We now know that 23 = (x - 35), so let’s write and solve the equation for it
23 = x-35
Add 35 on each side
X = 58
To solve this problem, we make use of the formula of
combination.
nCr = n! / r! (n – r)!
where n is the total number of subject teachers and r is
the number of subjects r = 1
For the English class n = 3
3C1 = 3! / 1! (3 – 1)! = 3
For the Algebra class n = 4
4C1 = 4! / 1! (4 – 1)! = 4
For the Biology class n = 2
2C1 = 2! / 1! (2 – 1)! = 2
The total number of different schedules would be the
product of the three combinations:
total combinations possible = 3 * 4 * 2
total combinations possible = 24
