Answer:
an = 63(-1/3)^(n-1)
Step-by-step explanation:
This is a geometric sequence with first term 63 and common ratio -1/3.
The equation for the nth term is
an = 63(-1/3)^(n-1).
For rhombus A:
base = 7 in
area = 35 in²
Area of rhombus = b * h
⇒ 35 = 7 * h
⇒ h = 35/7
⇒ h = 5 in
Rhombus B:
height = 3*5 = 15 in
base = 7*3 = 21 in
Area = 15 * 21 = 315 in²
Area
of rhombus B is 9 times area of rhombus A. When the dimensions are
increased to 3 times the initial dimension, area became 9 times.
Answer:
hope this will help u.. :-)
Step-by-step explanation:
There are infinitely many ways to do this. One such way is
(x^2 + 10x + 4) plus (-x^2 - 10x)
note how the x^2 terms combine to 0x^2 or just 0. The same applies to the x terms as well. The only thing left is 4
So as you can see, the goal is to get everything to cancel but the 4. You can also have something like
(2x^2-7x+2) plus (-2x^2 + 7x + 2)
and we have the same cancellations going on. This time we have 2+2 = 4 left over.
