Which of these organisms reproduce through binary fission? (Select all that apply.)

In a certain industrial process involving a heterogeneous catalyst, the volume of the catalyst (in the shape of a sphere) is 10.

trasher [3.6K]

Answer:

The second run will be faster - true, the increased surface area of catalyst will increase the rate of reaction

The second run will have the same rate as the first - possible, in case there is a factor other than catalyst limiting the reaction

The second run has twice the surface area - yes, 44 sqcm to 22 sqcm

Explanation:

A catalyst is a material which speeds up a reaction without being consumed in the process. A heterogeneous catalyst is one which is of a different phase than the reactants. The effectiveness of a catalyst is dependent on the available surface area. The first step for this question is to determine the total available surface area of catalyst in both processes.

Step 1: Determine radius of large sphere

$V_{L}=\frac{4}{3}*pi*{r_{L}}^{3}$

$10=\frac{4}{3}*pi*{r_{L}}^{3}$

${r_{L}}^{3}=\frac{7.5}{pi}$

$r_{L}=1.337cm$

Step 2: Determine surface area of large sphere

$A_{L}=4*pi*{r_{L}}^{2}$

$A_{L}=4*pi*1.337^{2}$

$A_{L}=22.463 cm^{2}$

Step 3: Determine radius of small sphere

$V_{s}=\frac{4}{3}*pi*{r_{s}}^{3}$

$1.25=\frac{4}{3}*pi*{r_{s}}^{3}$

${r_{s}}^{3}=\frac{0.9375}{pi}$

$r_{s}=0.668cm$

Step 4: Determine surface area of small sphere

$A_{s}=4*pi*{r_{s}}^{2}$

$A_{s}=4*pi*0.668^{2}$

$A_{s}=5.607 cm^{2}$

Step 5: Determine total surface area of 8 small spheres

$A_{S}=8*A_{s}$

$A_{S}=8*5.607$

$A_{S}=44.856 cm^{2}$

$A_{L}=22.463 cm^{2}$ - Surface area of 1 large sphere

$A_{S}=44.856 cm^{2}$ - Surface area of 8 small spheres

Options:

The second run will be faster - true, the increased surface area of catalyst will increase the rate of reaction
The second run will be slower - false, the increased surface area of catalyst will increase the rate of reaction
The second run will have the same rate as the first - possible, in case there is a factor other than catalyst limiting the reaction
The second run has twice the surface area - yes, 44 sqcm to 22 sqcm
The second run has eight times the surface area - no, 44 sqcm to 22 sqcm
The second run has 10 times the surface area - no, 44 sqcm to 22 sqcm

7 0

3 years ago

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Color change is most indicative of which type of chemical reaction?

makvit [3.9K]

Answer; chemical reaction

4 0

2 years ago

What is the mass in 6.34x10^23 molecules of calcium chloride

Liono4ka [1.6K]

Answer : The mass of calcium chloride is, 116.84 grams

Solution : Given,

Molar mass of calcium chloride, $CaCl_2$ = 110.98 g/mole

Number of molecules of calcium chloride = $6.34\times 10^{23}$

As we know that,

1 mole of calcium chloride contains $6.022\times 10^{23}$ molecules of calcium chloride

or,

1 mole of calcium chloride contains 110.98 grams of calcium chloride

Or, we can say that

As, $6.022\times 10^{23}$ molecules of calcium chloride present in 110.98 grams of calcium chloride

So, $6.34\times 10^{23}$ molecules of calcium chloride present in $\frac{6.34\times 10^{23}}{6.022\times 10^{23}}\times 110.98=116.84grams$ of calcium chloride

Therefore, the mass of calcium chloride is, 116.84 grams

6 0

3 years ago

1. A 25 g rock is placed in a graduated cylinder with water. The volume of the liquid rises from 18.3 mL to 21.4 mL Calculate th

MaRussiya [10]

Answer:

1. $\rho=8.06g/cm^3$

2. $H=10cm$

Explanation:

Hello,

1. In this case, since the volume of the rock is obtained via the difference between the volume of the cylinder with the water and the rock and the volume of the cylinder with the water only:

$V=21.4mL-18.3mL=3.1mL$

Thus, the density turns out:

$\rho=\frac{m}{V}=\frac{25g}{3.1cm^3} \\\\\rho=8.06g/cm^3$

2. In this case, given the density and mass of aluminum we can compute its volume as follows:

$V=\frac{m}{\rho}=\frac{1080g}{2.7g/cm^3}=400cm^3$

Moreover, as the volume is also defined in terms of width, height and length:

$V=W*H*L$

The height is computed to be:

$H=\frac{V}{L*W}=\frac{400cm^3}{5cm*8cm}\\ \\H=10cm$

Best regards.

3 0

2 years ago

Why was Niels Bohr’s atomic model superior to all the earlier models?

gladu [14]

1) it explains about stability of an atom by including stationary state.
2) it explains tge quantization of energy.
3) it gives the concept of angular momentum of a revolving electron.

6 0

2 years ago

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