Copper (II) sulfate pentahydrate may be heated to drive off the water of hydration. If 5 g of water are produced, what was the o
riginal weight of the copper (II) sulfate pentahydrate (CuSO4 • 5H2O)? CuSO4 • 5H2O → CuSO4 + H2O. The answer given was 13.9g. Can someone explain how this answer is found?
1 answer:
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First we need to calculate the number of moles of FeS:
number of moles = mass (grams) / molecular mass (g/mol)
number of moles of FeS = 198.2/120 = 1.65 moles
From the chemical reaction we deduce that:
if 4 moles of FeS produces 8 moles of SO
then 1.65 moles of FeS produces X moles of SO
X = (1.65×8)/4 = 3.3 moles of SO
Now we can calculate the mass of SO:
mass (grams) = number of moles × molecular mass (grams/mole)
mass of SO = 3.3×64 = 211.2 g