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Tom [10]
3 years ago
11

An aqueous solution is made by dissolving 29.4 grams of aluminum acetate in 433 grams of water. The molality of aluminum acetate

in the solution is
Chemistry
1 answer:
klasskru [66]3 years ago
4 0

Answer:

0.333 m

Explanation:

Molality (m) is moles of solute over kilograms of solvent.

Convert grams of the solute (aluminum acetate) to moles.

(29.4 g)/(204.11 g/mol) = 0.144 mol

Convert grams of the solvent (water) to kilograms.

433 g = 0.433 kg

Divide the solute by the solvent.

(0.144 mol)/(0.433 kg) = 0.333 m

The molality of the solution is 0.333 m.

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a particular application calls for N2 g with a density of 1.80 g/L at 32 degrees C what must be the pressure of the n2 g in mill
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Answer:

1223.38 mmHg

Explanation:

Using ideal gas equation as:

PV=nRT

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Also,  

Moles = mass (m) / Molar mass (M)

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PM=dRT

Given that:-

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The conversion of T( °C) to T(K) is shown below:

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So,  

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Applying the equation as:

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