Answer:
The density of the block is 2.827 grams/ cubic inch
Explanation:
The density of the block can be obtained by dividing the given mass of the block by its volume.
Density = mass / volume
The mass of the block given is 435.5 grams
The volume of the block can be obtained by using the formula:
Volume = Length X breadth X height
Volume = 3.5 X 8 X 5.5 = 154
There fore the density will be 435.5 / 154 = 2.827 grams/ cubic inch
Answer:
2 Cu2O + C → 4 Cu + CO2
This is an oxidation-reduction (redox) reaction:
4 CuI + 4 e- → 4 Cu0 (reduction)
C0 - 4 e- → CIV (oxidation)
Cu2O is an oxidizing agent, C is a reducing agent.
Explanation:
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The grams of Na that are needed to complete to react with 40..0 g of O2 is calculated as below
find the moles of O2 used = mass/molar mass
= 40 g/32g/mol = 1.25 moles
write the reacting equation
4Na+ O2 = 2Na2O
by use of mole ratio between Na to O2 which is 4 :1
the moles of Na = 1.25 x 4 = 5 moles
mass of Na = mass x molar mass
= 5 moles x 23 g /mol= 115 moles
Answer:
10.87 g of Ethyl Butyrate
Solution:
The Balance Chemical Equation is as follow,
H₃C-CH₂-CH₂-COOH + H₃C-CH₂-OH → H₃C-CH₂-CH₂-COO-CH₂-CH₃ + H₂O
According to equation,
88.11 g (1 mol) Butanoic Acid produces = 116.16 g (1 mol) Ethyl Butyrate
So,
8.25 g Butanoic Acid will produce = X g of Ethyl Butyrate
Solving for X,
X = (8.25 g × 116.16 g) ÷ 88.11 g
X = 10.87 g of Ethyl Butyrate
Answer:
-375.9_KJ/(mol)
Explanation:
H(T2 ) ≈ H(T1)+CPΔT
Specific heat of Carbon is 0.71 J/g K.
At 283.15 the heat capacity is 37.12 J/(mol*K)
Kirchhoff's law
H(T2 ) ≈ H(T1)+CPΔT
Where
H(T1) and H(T2 ) are the heat of formation of CO2 at temperatures T1 and T2
CP is the heat capacity
Thus we have and ΔT is the temperature change
H(T2 ) ≈ -393.51×10^3+CP×(500-25)
= -393.51×10^3+37.12×(500-25)
= -375878 J/(mol)
= -375.9KJ/(mol)