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luda_lava [24]
3 years ago
13

Why does the high pressure air being released into the ballast tanks of a submarine cause it to rise quickly?

Chemistry
1 answer:
Diano4ka-milaya [45]3 years ago
6 0

Answer:

Initially, the ballast tanks are filled with water. The weight of the submarine is equal to the upthrust of the water at the position of the submarine under water. When high pressure air is released into the ballast tanks displacing the water, the weight of the submarine becomes less than  the upthrust of the water thus the net force is is upwards and it forces the sub to resurface. This is according to the Archimedes principle which states that a a body partially or wholly immersed in water displaces its own weight of the fluid in which it is immersed.

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Consider the reaction. 2 Pb ( s ) + O 2 ( g ) ⟶ 2 PbO ( s ) An excess of oxygen reacts with 451.4 g of lead, forming 367.5 g of
Art [367]

Answer : The percent yield of the reaction is, 75.6 %

Solution : Given,

Mass of Pb = 451.4 g

Molar mass of Pb = 207 g/mole

Molar mass of PbO = 223 g/mole

First we have to calculate the moles of Pb.

\text{ Moles of }Pb=\frac{\text{ Mass of }Pb}{\text{ Molar mass of }Pb}=\frac{451.4g}{207g/mole}=2.18moles

Now we have to calculate the moles of PbO

The balanced chemical reaction is,

2Pb(s)+O_2(g)\rightarrow 2PbO(s)

From the reaction, we conclude that

As, 2 mole of Pb react to give 2 mole of PbO

So, 2.18 mole of Pb react to give 2.18 mole of PbO

Now we have to calculate the mass of PbO

\text{ Mass of }PbO=\text{ Moles of }PbO\times \text{ Molar mass of }PbO

\text{ Mass of }PbO=(2.18moles)\times (223g/mole)=486.1g

Theoretical yield of PbO = 486.1 g

Experimental yield of PbO = 367.5 g

Now we have to calculate the percent yield of the reaction.

\% \text{ yield of the reaction}=\frac{\text{ Experimental yield of }PbO}{\text{ Theoretical yield of }PbO}\times 100

\% \text{ yield of the reaction}=\frac{367.5g}{486.1g}\times 100=75.6\%

Therefore, the percent yield of the reaction is, 75.6 %

3 0
3 years ago
Explain Wurtz reaction with an example ~​
Deffense [45]

Wurtz reaction is a special type of organic reaction involving the synthesis of aliphatic hydrocarbons from two molecules of an alkyl halide and two atoms of sodium in the presence of dry ether solution

Please bear in mind that wurtz reaction fails whenever tertiary alkyl halides are used.

An example of Wurtz reaction is given below:

2R – X + 2Na → R–R + 2Na + X−

<h3>What are organic compounds?</h3>

Organic compounds can simply be defined as those classes of organic molecules which contain carbon atoms covalently bonded to hydrogen atoms (C-H bonds).

Below are some few general characteristics of organic compounds:

  • All organic compounds contain carbon.

  • Most of them are flammable.

  • They are all soluble in non-polar solvents

  • Most organic compounds / substances are covalently bonded molecules

Some classes of organic compounds are:

  • Alkanes
  • Alkenes
  • Alkenes

So therefore, Wurtz reaction is a special type of organic reaction involving the synthesis of aliphatic hydrocarbons from two molecules of an alkyl halide and two atoms of sodium in the presence of dry ether solution

Learn more about organic compounds:

brainly.com/question/704297

#SPJ1

5 0
2 years ago
If you sprayed an air freshener, where would the highest concentration of air freshener be found?
Hunter-Best [27]

FLOOR. Most of the molecules that dont sick to something fall on the floor so most would be on the FLOOR.

7 0
3 years ago
What's the net force acting on an 18-kg object if an acceleration of 3.0 m/s2 is produced? A. 12 N B. 6 N C. 54 N D. 36 N
ASHA 777 [7]
Im sure the answer is c

6 0
3 years ago
Read 2 more answers
a compound is decomposed In the laboratory and produces 1.40 g N and 0.20g H what is the empirical formula
Bumek [7]

First, find the number of moles for each element. The molar mass for nitrogen is 14 g/mol and that of hydrogen is 1 g/mol.

1.40 g N / 14 g/mol = 0.1 mol N

0.20 g H / 1 g/mol = 0.2 mol H

Find the mole ratio. Divide both numbers with the much lower value. In this case, it is 0.1 mol N.

For N: 0.1 ÷ 0.1 = 1

For H: 0.2÷0.1 = 2

Thus, the empirical formula is NH_{2}.

7 0
3 years ago
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