Answer:
The factors on which the amount of energy absorbed by an endothermic reaction depends are the " physical state of the reactant and the difference in the potential energy of the reactant and the product".
Explanation:
In an endothermic reaction the factors that affects the reaction are the physical state of the reactant, which thus becomes the enthalpy. And the difference in potential energy of the reactant because if the sum of the potential energy is less than the sum of the potential energy of the product than the endothermic reaction will be positive and the reaction hence will be endothermic.
=
- 
A good example of equilibrium would be the mixing of oil and water in a closed container.
<h3>What is chemical equilibrium?</h3>
Chemical equilibrium is a condition in which the concentrations of components of a chemical reaction remain unchanged and have no tendency to change.
Of all the options, the only one where the concentrations of the component reactants cannot change is a mixture containing oil and water in a closed container.
Oil and water are immiscible and thus, their concentrations remain constant.
More on chemical equilibrium can be found here: brainly.com/question/4289021
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Chlorine.
Chlorine is the 17th element and has a mass of 35.
Answer: The potential of the following electrochemical cell is 1.08 V.
Explanation:
=-0.74V[/tex]
=0.34V[/tex]
The element with negative reduction potential will lose electrons undergo oxidation and thus act as anode.The element with positive reduction potential will gain electrons undergo reduction and thus acts as cathode.
Here Cr undergoes oxidation by loss of electrons, thus act as anode. copper undergoes reduction by gain of electrons and thus act as cathode.


Where both
are standard reduction potentials, when concentration is 1M.
![E^0=E^0_{[Cu^{2+}/Ni]}- E^0_{[Cr^{3+}/Cr]}](https://tex.z-dn.net/?f=E%5E0%3DE%5E0_%7B%5BCu%5E%7B2%2B%7D%2FNi%5D%7D-%20E%5E0_%7B%5BCr%5E%7B3%2B%7D%2FCr%5D%7D)

Thus the potential of the following electrochemical cell is 1.08 V.