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yan [13]
1 year ago
15

Describe two ways that can be used to identify which layer is organic and which layer is the aqueous layer in a liquid-liquid ex

traction.
Chemistry
1 answer:
mash [69]1 year ago
8 0

Two ways that can be used to identify which layer is organic and which layer is the aqueous layer in a liquid-liquid extraction are:

There are many methods that can be used to distinguish two layers from each other using contrast between the two substances in certain properties. One of the common methods that can be used to distinguish aqueous layer from an organic layer is adding water to mixture and observing which layer increases in size. The layer that increases in the size is the aqueous layer, as water is immiscible with organic layer. Thus, water can only increase aqueous layer. Another way is, for a start, the ethereal layer, even laden with organic solute, should be less dense than aqueous layer, and thus should be floating on top. Sometimes you can even tell by rubbing solvent with your fingers.

<h3>What is extraction?</h3>

Extraction is a process used in organic chemistry for isolating a certain substance or a compound from its source material. Since the source material is composed of the various molecules and compounds but only a specific compound is needed, the desired compound has to be separated from the mixture.

A liquid-liquid extraction method is a method used to extract substance using the two immiscible of different natures. Since two liquids are immiscible, they liquids form the two layers when added to the same vessel. This is typically done using the water and an organic solvent that is insoluble in water. When two are mixed, they form an aqueous layer and an organic layer.

To know more about extraction visit: brainly.com/question/12910778

#SPJ4

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3 years ago
A 13 g sample of P4010 contains how many
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Answer:

\large \boxed{5.5 \times 10^{22}\text{ molecules of P$_{2}$O}_{5}}

Explanation:

You must calculate the moles of P₄O₁₀, convert to moles of P₂O₅,  then convert to molecules of P₂O₅.

1. Moles of P₄O₁₀

\text{Moles of P$_{4}$O}_{10} = \text{13 g P$_{4}$O}_{10} \times \dfrac{\text{1 mol P$_{4}$O}_{10}}{\text{283.89 g P$_{4}$O}_{10}} = \text{0.0458 mol P$_{4}$O}_{10}

2. Moles of P₂O₅

P₄O₁₀ ⟶ 2P₂O₅

The molar ratio is 2 mol P₂O₅:1 mol P₄O₁₀

\text{Moles of P$_{2}$O}_{5} = \text{0.0458 mol P$_{4}$O}_{10} \times \dfrac{\text{2 mol P$_{2}$O}_{5}}{\text{1 mol P$_{4}$O}_{10}} = \text{0.0916 mol P$_{2}$O}_{5}

3. Molecules of P₂O₅

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